Answered: A 400-N weight starts down the incline…

Name: ANSWERS MUST BE IN 3 DECIMAL PLACES1. A 400-N weight starts down the i
Uploaded: 2024-03-20T06:57:57.000Z
Channel: Bartleby
Description: ANSWERS MUST BE IN 3 DECIMAL PLACES1. A 400-N weight starts down the incline of 30o with the horizontal with an initial velocity of 4m/s. Find the velocity of the weight after 10s if fk = 0.2 for the incline.2. A 400-N body starts up the incline of 3

Science

Physics

A 400-N weight starts down the incline of 30o with the horizontal with an initial velocity of 4m/s. Find the velocity of the weight after 10s if fk = 0.2 for the incline.

College Physics

10th Edition

ISBN:9781285737027

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter4: The Laws Of Motion

Section: Chapter Questions

Problem 17P: (a) Find the tension in each cable supporting the 6.00 102-N cat burglar in Figure P4.35. (b)...

See similar textbooks

Similar questions

ANSWERS MUST BE IN 3 DECIMAL PLACES 1. A 400-N body starts up the incline of 30o with the horizontal (fk = 0.2) with a velocity of 3m/s. How long must a 500-N horizontal force act on the body to increase its velocity to 8m/s? 2.. A 400-N body starts up the incline of 30o with the horizontal (fk = 0.2) with a velocity of 3m/s. How far will the body travel while the force is acting?
A 44.6 kg box is given a 130.4 N horizontal force to the left and a 383.5 N force to the right at an angle of 53.1° above the horizontal. Neglecting friction, what is the magnitude of the acceleration? Use g=9.8m/s
A 2kg box is being pulled up a ramp by a force of 24N. The ramp is at an angle of 35 degrees from the ground. The force of friction on the box is 1.5N. What is the magnitude and direction of the component of gravity in the x-direction?
A .22 caliber rifle bullet traveling at 350 m/s, strikes a large tree and penetrates it to a depth of 0.130 m. The mass of the bullet is 1.80 g. Assume a constant retarding force. How much time is required for the bullet to stop? What force, in newtons, does the tree exert on the bullet?
A 2kg box is being pulled up a ramp by a force of 24N. The ramp is at an angle of 35 degrees from the ground. The force of friction on the box is 1.5N. What is the net horizontal force in the x-direction? What is the magnitude of the normal force acting on the block?
World-class sprinters can accelerate out of starting blocks with an acceleration that is nearly horizontal and has magnitude 15m/s². How much horizontal force must a 55 kg sprinter exert on the starting blocks during a start to produce this acceleration?
In the wheelbarrow, the load has a perpendicular lever arm of 7.50 cm, while the hands have a perpendicular lever arm of 1.02 m. (a) What upward force must you exert to support the wheelbarrow and its load if their combined mass is 45.0 kg? (b) What force does the wheelbarrow exert on the ground?
A ?=1.55 object hangs in equilibrium at the end of a rope (taken as massless) while a wind pushes the object with a ?W=13.5 horizontal force. Find the magnitude of the tension in the rope and the rope's angle from the vertical. The acceleration due to gravity is ?=9.81.
A 5kg block is pulled westward across a frictionless horizontal surface by a 30 N force applied at 87° angle above the horizontal? What is the block's acceleration? What is the normal force?
A girl is sledding down a slope that is inclined at 30º with respect to the horizontal. The wind is aiding the motion by providing a steady force of 197 N that is parallel to the motion of the sled. The combined mass of the girl and the sled is 79.1 kg, and the coefficient of kinetic friction between the snow and the runners of the sled is 0.289. How much time is required for the sled to travel down a 164-m slope, starting from rest?
** I am confused on this being below the horizontal. Is that making Fy a negative? If so, would that then affect the calculation for normal force? A box (M = 4 kg) is resting on a frictionless horizontal surface. Then there is a 25 Newton force acting onit at an angle 35 degrees below the horizontal.1. Find the horizontal component of the force, Fx - I have Fcostheta so 25cos35 = 20.479 N2. Find the vertical component of the force, Fy - I don't know if this should be 25sin35 or 25sin(-35) 3. Find the normal force acting on the box - Fn = mg - Fy (but I do not understand if this is going to be a positive or negative Fy, obviously negative would make this mg + Fy)4. Find the acceleration of the box5. Find the distance it will travel in 3 seconds.
A baseball pitcher throws a ball straight up into the air at a speed of 21.5 m/s. In the process, he moves his hand through a distance of 2.00 m. If the ball has a mass of 0.250 kg, find the force he exerts on the ball to give it this upward speed. (Report answer to 3SF; unit: N)