que is developed.Ans[1440 r.p.m.]A 440 V, 3-phase, 50 Hz, 4-pole, Y-connected induction motor has a full-load speed of 1425r.p.m.the rotor has an impedance of (0.4 +j 4) Q and rotor/stator turns ratio is 0.8. Calculate (i) full loadAns[78.87N.m ; 22.73A, 620w]Q10/torque ,(ii) rotor curren (iii) full load rotor Cu loss.O11/L A 3-nhase induction motor

Answered: Image /qna-images/answer/772042e5-47e9-4f2b-928a-dd46c8a28fef.jpg

A 440 V, 3-phase, 50 Hz, 4-pole, Y-connected induction motor has a fu the rotor has an impedance of (0.4 +j 4) 2 and rotor/stator turns ratio is torque ,(ii) rotor curren (iii) full load rotor Cu loss. L]suy

A 440 V, 3-phase, 50 Hz, 4-pole, Y-connected induction motor has a fu the rotor has an impedance of (0.4 +j 4) 2 and rotor/stator turns ratio is torque ,(ii) rotor curren (iii) full load rotor Cu loss. L]suy

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Similar questions

QI: The parameters of a 4 kW, 220V. 2-phase induction motor, in ohms per phase, are: r1=0.53, x1 =2.4, XM= 70, r2 = 0.96, x2 = 3.0. The motor is operated from unbalanced 2- phase source whose voltages are 230V and 210V, the smaller voltage is lagging the larger by 800. For a slip of 5% and rotational losses of 30 W, find the positive- and negative- sequence components of: (a) the applied voltages. (b) Find the values of phase currents (c) the input current. (d) Find the developed mechanical power. (e) Find the efficiency.
A certain six-pole 440-V-rms 60-Hz three-phase delta-connected induction motor has Rs=0.08 ΩRr′=0.06 Ω Xs=0.20 ΩXr′=0.15 Ω Xm=7.5 Ω Neglecting the rotational losses, find the no-load speed, line current, and power factor for the motor.
The stator resistance of a 1-phase induction motor is 2.5 ohms and its leakage reactance is 2.0 ohms. Onno-load, the motor takes 4 A at 96 V and at 0.25 lagging power factor. The no-load friction andwindage loss is negligible. Under the blocked-rotor condition, the input power is 130 W at 6 A and42 V. Obtain the equivalent circuit parameters.
An induction motor draws 50 A from a 450 V, three-phase line at a lagging power factor of0.75. Its stator and rotor copper losses are 950 W and 500 W, respectively. Its core lossesare 400 W, the friction and windage losses are 150 W. Determine the following(a) The air-gap power and the developed mechanical power.(b) The shaft output power and the motor efficiency
A 230 V single-phase induction motor has the following parameters: R1 =R2= 11 ohms, X1 = X2 = 14 ohms and Xm =220 ohms. With 8% slippage, calculate:1. The impedance of the anterior branch2. Posterior branch impedance3. Total impedance4. The input current module5. Power factor6. Input power7. Power developed8. The torque developed at nominal voltage and with a speed of 1728 rpm ..
A 6-pole, 3-phase induction motor develops a power of 22.38kW, including mechanical losses which total 1.492 kW at a speed of 950 rpm on 550-V, 50 Hz mains. The power factor is 0.88. Calculate for this load (a) the slip (b) the rotor copper loss (c) the total input if the stator losses are 2000 W (d) the efficiency (e) the line current (1) the number of complete cycles of the rotor electromotive force per minute. [(a) 0.05 (b) 1175 (c) 25.6 kW (d) 82% (e) 30.4 A (1) 150
a)the figure below shows the per-phase equivalent circuit of a two - pole three- phase induction motor operating at 50 Hz . The voltage (E1) across the magnetizing inductance is 210 v , and the slip (s) is 0.05 . What is the developed torque produced by the motor ? b) A 4 poles , 50Hz , Y-connected three phase induction motor has the per phase equivalent circuit parameters of (R1 =R2=0.12 , X1=X2=0.6 , Xm =12 ) ohm and I2 =20 (0 . Use exact equivalent circuit to determine the following at rated slip of 0.03 : I. Stator current II. Magnetizing current III. Power factor IV. Developed torque C) What is the physical meaning for each of the following induction motor parameters : R1 , R2 , Rc , X1 , X2 , Xm d) What is synchronous watt
A three-phase induction motor having a synchronous speed of 1000 revolution per minutedraws 50 kW from a three-phase feeder. The copper losses and iron losses in the stator amount to 5 kW. If the motor runs at 880 r/min.a. The rotor I2R losses b. The mechanical power developed c.The mechanical power delivered to the load, knowing that the windage and friction losses are equal to 2 kW
230 V, 50 Hz, 4 – pole single-phase induction motor has the following equivalent circuit impedances:R1 = 2.22, R2 = 4.52, X1 = 3.12, X2 = 2.62, XM = 802, Friction, windage and core loss = 40 W. For a slip of 0.03pu, calculation (a) input current, (b) power factor, (c) developed power, (d) output power, (e) efficiency.
A three-phase, four-pole induction motor, connected at ∆, 220V, 60Hz, presents rotational losses of 300W when operating with a slip of 2.5%. It is known that the motor has the following parameters per phase: r1 = r2′ = 0.5Ω, x1 = x′2 = 1jΩ, rc = 107Ω xφ = 10jΩ. Under these conditions, calculate: (a) The line current supplied by the mains to the motor. (b) Engine efficiency. (c) Assume the motor starts at a standstill, find the starting line current. (d) Assume that the motor starting torque is greater than the load torque. Describe what happens between the moment of starting and the moment when the engine reaches the operating point. Discuss the relationship between motor speed, slip, and the current required from the network. ..
3. A group of induction motors rated 2200-V, 3-phase, 60 Hz delivers a total of 600 HP and is operating at an average power factor of 0.8 lagging. If half of this total load is replaced by a group of synchronous motors operating at 0.8 leading, determine the difference in the line current? Assume all motors operate at an average efficiency of 90%.
A 3-phase, 6 pole, 440 V, 60 Hz, Y-connected induction motor has the following impedances per phase referred to the stator circuit: R1=0.43 Ω, R2=0.54 Ω, X1=1.263 Ω, X2=0.608 Ω, XM=43Ω The total rotational losses are 1100 W and are assumed to be constant. The core loss is lumped in with the rotational losses. For a rotor slip of 2 percent at the rated voltage and rated frequency, Find the motor speed, stator current, output power