A 45-caliber bullet shot straight up from thesurface of the moon would reach a height of s = 832t - 2.6t^2 ftafter t sec. On Earth, in the absence of air, its height would bes = 832t - 16t^2 ft after t sec. How long will the bullet be aloft ineach case? How high will the bullet go?

A 45-caliber bullet shot straight up from thesurface of the moon would reach a height of s = 832t - 2.6t^2 ftafter t sec. On Earth, in the absence of air, its height would bes = 832t - 16t^2 ft after t sec. How long will the bullet be aloft ineach case? How high will the bullet go?

College Algebra

10th Edition

ISBN:9781337282291

Author:Ron Larson

Publisher:Ron Larson

Chapter1: Equations, Inequalities, And Mathematical Modeling

Section1.1: Graphs Of Equations

Problem 9ECP

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Question

A 45-caliber bullet shot straight up from the
surface of the moon would reach a height of s = 832t - 2.6t^2 ft
after t sec. On Earth, in the absence of air, its height would be
s = 832t - 16t^2 ft after t sec. How long will the bullet be aloft in
each case? How high will the bullet go?

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