A 45.0 mL sample of 0.456 M ascorbic acid, HC6H706, was titrated with 0.332 M KOH solution. Ka = 8.0 x 105 a. Using an ICE box and balanced chemical equation show the number of moles of each substance at equilibrium after 20.0 mL of KOH was added to the ascorbic acid. Spectator ions should be left out of the equation. b. Explain why the mixing of 45.0 mL of 0.456 M ascorbic acid and 20.0 ml of 0.332 M KOH resulted in the formation of a buffer? C. Determine the pH after the addition of 75.0 mL of 0.332 M KOH to 45.0 mL of 0.456 M ascorbic acid solution.

Q: 1. How many moles of Ca2+ and OH- ions are produced for every one mole of Ca(OH)2 that dissolves in…

A: Since there are multiple questions, we will answer only the first questions (no. 1). If you require…

Q: B. In an acid-base titration, a solution of 50.0 ml of hydrochloric acid is completely neutralized…

A: Given:  The volume of HCl = 50 mL The volume of KOH = 25 mL The concentration of KOH = 0.80 M

Q: H.Ws: 1- What is the influence of adding buffers on the chemical solutions? Give an example of oil…

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Q: Which of the following mixtures of acids exhibit(s) two end points when titrated with 0.10 M NAOH? O…

A: Option b is correct.

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A: Added NaOH is reacts with salt. For pH  calculation using Henderson Hasselbalch equation.

Q: 1. Calculate the pH at the following points in the titration of 55.8 mL of a 0.0350 molar acetic…

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Q: What mass of ammonium chloride should be added to 2.55 L of a 0.145 M NH3 to obtain a buffer with a…

A: As we know, pKb=-logKb and, pOH=pKb + logSalt[Base]

Q: What is the molar solubility of Ca(OH)2Ca(OH)2? Ksp=8.0x10−6

A: Note: As per our guidelines, we are supposed to answer only one question when multiple questions are…

Q: Consider the reaction of a 20.0 mL of 0.220 M C₅H₅NHCl (Ka = 5.9 x 10⁻⁶) with 12.0 mL of 0.211 M…

A: Explanation: Molarity is defined as moles of solute, which in your case is sodium hydroxide,…

Q: Consider the titration of a 50.0-mL sample of 0.0500 M HCI with a 0.0250 M NaOH solution. What is…

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Q: You have been provided with a 35.0 mL sample of hydrochloric acid (HCl) of unknown concentration.…

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Q: Consider the titration of a 60.0 mL of 0.291 M weak acid HA (Ka = 4.2 x 10⁻⁶) with 0.400 M KOH. What…

A: The question is based on the concept of titrations. we have been given a weak Acid which is titrated…

Q: Volume transferred, mL Solution Buffer a Buffer b 0.100 М СН,СООН 40.0 40.0 0.100 M NaOH 20.0 30.0…

A: We have to use henderson hasselbalch equation to calculate the pH of buffer. We need to calculate…

Q: Laboratory Experiments 75 5. Sodium carbonate is a reagent that may be used to standardize acids in…

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Q: 4. If an unknown organic acid is titrated with 0.200 M NaOH and it takes 34.50 mL to reach the…

A: For such kind of questions, we know that the amount of NaOH multiplied with its molarity will give…

Q: If you have a 74.0 mL solution of 0.160 M benzoic acid, C6H5 COOH, and it is being titrated with…

A: Given: Concentration of benzoic acid (Assuming HA) = 0.160 M Volume of HA solution = 74.0 mL = 0.074…

Q: A buffer solution, consisting of a weak acid and its conjugate salt is to be prepared with a pH…

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Q: A 0.600 g sample of a pure, weak monoprotic acid gives end points at 40.0 mL when it is titrated…

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Q: . What is the pH of a buffer prepared by adding 0.405 mol of the weak acid HA to 0.507 mol of NaA in…

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Q: A student wants to prepare a 400 mL of 1.00 M buffer with a pH of 3.2. Which of the following…

A: A buffer is a solution which resist change in pH and obtained when a weak acid and the salt of its…

Q: 4. The slightly soluble salt AB2 ionizes as shown. (1) AB, (s) = A²* (aq.) + 2B° (aq.) When a…

A: Note: As per company policy we are supposed to attempt first three subparts only. Please repost…

Q: Consider the titration of 30.0 mL of 0.269 M weak base B (Kb = 1.3 x 10⁻¹⁰) with 0.150 M HI. A)…

A: Hello. Since your question has multiple sub-parts, we will solve first three sub-parts for you. If…

Q: Consider the titration of a 40.0 mL of 0.189 M weak acid HA (Ka = 2.7 x 10⁻⁸) with 0.100 M LiOH. a.…

A: “Since you have posted a question with multiple sub-parts, we will solve the first three sub-parts…

Q: Consider a buffer made by adding 42.3 g of (CH3)2NH2I to 250.0 mL of 1.42 M (CH:)2NH (Kb = 5.4 x 10…

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Q: The molarity of a 10.00 mL aliquot of an unknown monoprotic acid titrated with 13.37 mL of 1.25 M…

A: Formula :-  Macid x Vacid = Mbase x Vbase    To calculate :- Macid

Q: What is the pH of a buffer that contains 0.15 M CH3COOH and 0.10 M NaCH3COO (K, = 1.8 x 10$)?

A: Given : Concentration of weak acid CH3COOH = 0.15 M And concentration of conjugate base salt of weak…

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A: Molarity - ratio of number of moles of solute to the volume of solution in litres. Formula is,

Q: Determine the parts per million of CO2 in the sample of air, given that the density of CO2 at the…

A:

Q: Average value of solubility product from titration: _________ Literature value for solubility…

A: The question is based on the concept of solubility product Principle.   it states that a weak…

Q: A buffer was prepared by adding 7.50 moles K2HPO4 and 9.60 mol KH2PO4 to a 1.0 L solution. Ka2 = 6.2…

A: the mentioned buffer is an acidic where KH2PO4 is the weak acid and K2HPO4 is the salt component.

Q: 4. In an experiment to determine the concentration of an HCCI sample of unknown concentration, 0.1 M…

A: The concentration of unknown solutions is calculated by using the process of titration. The…

Q: 1-that bond length is inversely related to bond strength, explain why HCl is stronger than HF?…

A: Since you have posted multiple question, the answer for first question is given below. Kindly repost…

Q: 20.00 mL of 0.0750 M benzoic acid ( C6H5COOH) is titrated with 0.0250 M NaOH. Ka benzoic acid = 6.5…

A: Given,  [C6H5COOH] = 0.0750 M  Volume of C6H5COOH in mL = 20.00 mL  [NaOH] = 0.0250 M  Acid…

Q: In the titration of a 25.0-mL sample of 0.115 M HNO, with 0.21 M NaOH, where K, HNO, = 4.6x104 %3D O…

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Q: 1) A 25.00 ml sample of unknown concentration of the glycolic acid, HOCH2COOH, was titrated to the…

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Q: Consider the titration of 30.0 mL of 0.275 M weak base B (Kb = 1.3 x 10⁻¹⁰) with 0.150 M HI. A.)…

A: The question is based on the concept of titrations. We are titrating a weak base with a strong acid.…

Q: A student set up a titration apparatus that involved using 25.9 mL of 1.57 M acetic acid. The acetic…

A: Given : volume of acetic acid = 25.9 ml Molarity of acetic acid = 1.57 M Molarity of NaOH =0.154 M…

Q: You have been provided with a 30.0 mL sample of hydrochloric acid (HCl) of unknown concentration.…

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Q: Consider the titration of 30.0 mL sample of 0.120 M CH3COOH with 0.240 M NaOH. Determine each…

A: This is a multipart question,,and as per guidelines I can only answer first three part,if you want…

Q: A 50.0 mL solution of 0.150 M acetic acid (CH3 COOH) is titrated with 0.150 M NaOH. What is the pH…

A: Final answer : 4.921

Q: A solution is prepared by dissolving 0.350 g of benzoic acid, HC7H5O2, in water to make 100.0 mL of…

A: Acid is one of those species that undergoes dissolution and releases H+ ions. When a certain…

Q: 1.A 25.8 mL aliquot of 0.03 M aqueous hydrochloric acid is titrated with 0.02 M NaOH (ac). What…

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Q: A general chemistry student performs a titration with 28.4 mL of 0.294 M weak acid solution with a…

A: Introduction The details and data about the H+ ions (hydrogen ions) are derived by deriving any…

Q: 2.5 20.00 mL of 0.0750 M benzoic acid ( C6H5COOH) is titrated with 0.0250 M NaOH. Ka benzoic acid =…

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Q: A chemist added 0.15 mol of NaOH to a 1.00 L buffer that contained 0.50 M propanoic acid HC3H5O2)…

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Q: A certain weak acid, HA, with a K. value of 5.61 x 10-6, is titrated with NaOH.

A:

Q: Consider the titrimetric determination of acetic acid (60.05 g/mol) in vinegar. Titration of a 5.00…

A: