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A 5 cm diameter potable water line is to be run through a maintenance room in a commercial building. Three possible layouts for the galvanized iron water line are proposed as shown in the figure. The bends are conventional threaded fittings. Select the option that minimizes losses and determine the pressure drop for a flow of 350 L/min.  For the elbo losses use, hℓm =

A 5 cm diameter potable water line is to be run through a maintenance room in a commercial building. Three possible layouts for the galvanized iron water line are proposed as shown in the figure. The bends are conventional threaded fittings. Select the option that minimizes losses and determine the pressure drop for a flow of 350 L/min.  For the elbo losses use, hℓm =

Automotive Technology: A Systems Approach (MindTap Course List)
Automotive Technology: A Systems Approach (MindTap Course List)
6th Edition
ISBN:9781133612315
Author:Jack Erjavec, Rob Thompson
Publisher:Jack Erjavec, Rob Thompson
Chapter36: Electric Vehicles
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Problem 8RQ: Which of the statements about hydrogen is true? a. A hydrogen atom is one proton and two electrons....
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A 5 cm diameter potable water line is to be run through a maintenance room in a commercial building. Three possible layouts for the galvanized iron water line are proposed as shown in the figure. The bends are conventional threaded fittings. Select the option that minimizes losses and determine the pressure drop for a flow of 350 L/min. 

For the elbo losses use, hℓm = 

5.25 m (a) Two 45° bends 2.5 m (b) A standard elbow (c) Three standard elbows
Transcribed Image Text:5.25 m (a) Two 45° bends 2.5 m (b) A standard elbow (c) Three standard elbows
hem 1 H|2 u²Kc 2
Transcribed Image Text:hem 1 H|2 u²Kc 2
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Step 1: Given data and the parameters need to find out Given: Pipe diameter, d = 5 cm = 0.05 mWater flow rate, Q=350 L/min Step 2: 1) Calculation for the suitable layout which minimizes the losses The average velocity of water through the pipe is, u = OKA Solution || 元4 xd² WAS THIS HELPFUL? - 350 × 10-³ 60 × 0.05² π - - 350 × 10-³ 60 3 -m³/sElevation difference betwee Step 3:2) calculation of pressure drop in each layout a Two 45° bends Applying Bernoulli's equation at the pipe inlet 1 and the pipe exit 2, Pg +Z₁ + V₂² 2.97 m/sUsing Loss coefficient data - P + Z₂ + 1/2/2 1 The head loss in the Two 45° bends is the minimum. Hence, the layout of two 45° bends should be s
Transcribed Image Text:Step 1: Given data and the parameters need to find out Given: Pipe diameter, d = 5 cm = 0.05 mWater flow rate, Q=350 L/min Step 2: 1) Calculation for the suitable layout which minimizes the losses The average velocity of water through the pipe is, u = OKA Solution || 元4 xd² WAS THIS HELPFUL? - 350 × 10-³ 60 × 0.05² π - - 350 × 10-³ 60 3 -m³/sElevation difference betwee Step 3:2) calculation of pressure drop in each layout a Two 45° bends Applying Bernoulli's equation at the pipe inlet 1 and the pipe exit 2, Pg +Z₁ + V₂² 2.97 m/sUsing Loss coefficient data - P + Z₂ + 1/2/2 1 The head loss in the Two 45° bends is the minimum. Hence, the layout of two 45° bends should be s
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