# A 5.0 g piece of metal is heated to 100 degrees Celsius, then placed in a beaker containing 20.0 g of water at 10 degrees Celsius. The temperature of the water rises to 15 degrees Celsius. Assuming that the heat lost by the metal = heat gained by the water. Calculate the specific heat of the metal.

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A 5.0 g piece of metal is heated to 100 degrees Celsius, then placed in a beaker containing 20.0 g of water at 10 degrees Celsius. The temperature of the water rises to 15 degrees Celsius. Assuming that the heat lost by the metal = heat gained by the water. Calculate the specific heat of the metal.

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Step 1

Given:

Specific heat of water = 4.18 J/g. oC

Mass of metal = 5.0 g

Mass of water = 20.0 g.

Initial Temperature of water = 10 oC

Initial Temperature of metal = 100 oC

Final temperature of water and meal = 15 °C

Step 2

Heat loss or gain i...

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### Chemical Thermodynamics 