A 5.80 µF , parallel-plate, air capacitor has a plate separation of 5.00 mm and is charged to a potential difference of 4.00x102 v. Calculate the energy density in the region between the plates. O u = 48.333 mJ/m3 O u = 38.333 mJ/m3 Ou = 28.333 mJ/m3 Ou = 18.333 mJ/m3

A 5.80 µF , parallel-plate, air capacitor has a plate separation of 5.00 mm and is charged to a potential difference of 4.00x102 v. Calculate the energy density in the region between the plates. O u = 48.333 mJ/m3 O u = 38.333 mJ/m3 Ou = 28.333 mJ/m3 Ou = 18.333 mJ/m3

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter19: Electric Potential And Electric Field

Section: Chapter Questions

Problem 15PE: The electric field strength between two parallel conducting plates separated by 4.00 cm is 7.50 104...

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Question

A 5.80 µF , parallel-plate, air capacitor has a plate separation of 5.00 mm and is charged to a potential difference of 4.00x102 v. Calculate the energy density in the region between the plates.
O u = 48.333 mJ/m3
O u = 38.333 mJ/m3
Ou = 28.333 mJ/m3
Ou = 18.333 mJ/m3

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