Question
Asked Oct 29, 2019
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A 55-kg pole vaulter running at 10 m/s vaults over the bar. Her speed when she is above the bar is 1.5 m/s. Neglect air resistance, as well as any energy absorbed by
the pole, and determine her altitude as she crosses the bar.
m
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A 55-kg pole vaulter running at 10 m/s vaults over the bar. Her speed when she is above the bar is 1.5 m/s. Neglect air resistance, as well as any energy absorbed by the pole, and determine her altitude as she crosses the bar. m

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Expert Answer

Step 1

The change in potential energy of the pole vaulter will be equal to her change in kinetic energy.

Assume the ground to be the position of zero potential energy. Then the equation for the conservation of energy is

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1 mgh-0m 2 2 Here, mis the mass of the pole vaulter, g is the acceleration due to gravity, h is the altitude when she crosses the bar, v, is the speed of the pole vaulter when she is above the bar and v, is her initial speed

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Step 2

Rewrite the above equ...

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mghm(v7-) h= 2g Take the upward direction to be positive so that the value of acceleration due to gravity will be 9.8 m/s2 Substitute the numerical values in the above equation (1.5 m/s)-(10 m/s) 2(-9.8 m/s h = = 4.99 m

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