A 60 kg person walking at 1 m/sec (~2mph) bumps into a wall and stops in adistance of 2.5cm in about 0.05 sec. what is the force developed on impact?A(mv) = (60 kg ) (1 m/sec) - (60 kg) (0 m/sec) = (60 kg.m/sec)%3D

. The resultant force applied is equal to the rate of change of momentum and it is given by the…

Answered: A 60 kg person walking at 1 m/sec…

Inquiry into Physics

8th Edition

ISBN:9781337515863

Author:Ostdiek

Publisher:Ostdiek

Chapter3: Energy And Conservation Laws

Section: Chapter Questions

Problem 2C: A bullet with a mass of 0.01 kg is tired horizontally into a block of wood hanging on a string. The...

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A bullet with a mass of 0.01 kg is tired horizontally into a block of wood hanging on a string. The bullet sticks in the wood and causes it to swing upward to a height of 0.1 m. If the mass of the wood block is 2 kg, what was the initial speed of the bullet?
A 0.0250-kg bullet is accelerated from rest to a speed of 550 m/s in a 3.00-kg rifle. The pain of the rifle's kick is much worse if you hold the gun loosely a few centimeters from your shoulder rather than holding it tightly against your shoulder. (a) Calculate the recoil velocity of the rifle if it is held loosely away from the shoulder. (b) How much kinetic energy does the rifle gain? (c) What is the recoil velocity if the rifle is held tightly against the shoulder, making the effective mass 28.0 kg? (d) How much kinetic energy is transferred to the rifle shoulder combination? The pain is related to the amount of kinetic energy, which is significantly less in this latter situation. (e) Calculate the momentum of a 110-kg football player running at 8.00 m/s. Compare the player's momentum with the momentum of a hard-thrown 0.410-kg football that has a speed of 25.0 m/s. Discuss its relationship to this problem.
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A 60 kg person walking at 1 m/sec (~2mph) bumps into a wall and stops in a distance of 2.5cm in about 0.05 sec. what is the force developed on impact? A(mv) = (60 kg ) (1 m/sec) - (60 kg) (0 m/sec) = (60 kg.m/sec) %3D