Question
Asked Oct 30, 2019
1 views

A 7.1 kg mass on a frictionless inclined surface
is connected to a 2.4 kg mass. The pulley is
massless and frictionless, and the connecting
string is massless and does not stretch. The
2.4 kg mass is acted upon by an upward force
of 8 N, and thus has a downward acceleration
of only 4.8 m/s^2.
The acceleration of gravity is 9.8 m/s^2.

What is the tension in the connecting string? Answer in units of N.

What is the angle θ? Answer in units of ◦

check_circle

Expert Answer

Step 1

Assuming to θ be the angle of the incline, for the 7.1 kg mass, the equation of motion is,

help_outline

Image Transcriptionclose

T+Mg sin Ma

fullscreen
Step 2

For the 2.4 kg mass, the equation of motion is,

help_outline

Image Transcriptionclose

mg-T-F ma

fullscreen
Step 3

From step 2, the t...

help_outline

Image Transcriptionclose

T=m(g-a)-F (2.4kg)(9.8m/s?-4.8m/s)-(8N) =4N

fullscreen

Want to see the full answer?

See Solution

Check out a sample Q&A here.

Want to see this answer and more?

Solutions are written by subject experts who are available 24/7. Questions are typically answered within 1 hour.*

See Solution
*Response times may vary by subject and question.
Tagged in

Science

Physics

Kinematics

Related Physics Q&A

Find answers to questions asked by student like you
Show more Q&A
add