1. A 70-kg ancient statue lies at the bottom of the sea. Its volume is 3.0 x 104 cm³. How much force isneeded to lift it? R.D. seawater = 1.0252. An iceberg of R.D. 0.92 floats in sea water of R.D. 1.024 with 10615 m³ immersed. Determine thefraction of the iceberg below the water line. Hence find the total volume of the iceberg.

Name: 1. A 70-kg ancient statue lies at the bottom of the sea. Its volume i
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Description: 1. A 70-kg ancient statue lies at the bottom of the sea. Its volume is 3.0 x 104 cm³. How much force isneeded to lift it? R.D. seawater = 1.0252. An iceberg of R.D. 0.92 floats in sea water of R.D. 1.024 with 10615 m³ immersed. Determine thefraction

Given mass m = 70 kg Volume V = 3×104 cm3 = 3×104 × 10-6 m3 = 3 × 10-2 m3 Density = R.D × density…

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A 70-kg ancient statue lies at the bottom of the sea. Its volume is 3.0 x 10* cm³. How much force is needed to lift it? R.D. seawater = 1.025

Inquiry into Physics

8th Edition

ISBN:9781337515863

Author:Ostdiek

Publisher:Ostdiek

Chapter4: Physics Of Matter

Section: Chapter Questions

Problem 25P: . A box-shaped piece of concrete measures 3 ft by 2 ft by 0.5 ft (a) What is its weight? (b) Find...

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