A 8.00-cm-long wire is pulled along a U-shapedconducting rail in a perpendicular magnetic field. Thetotal resistance of the wire and rail is 0.340 2. Pullingthe wire at a steady speed of v= 4.00 m/s causes4.30 W of power to be dissipated in the circuit./myct/itemView?assignmentProblemID=195605...34²F2A3ED80F3$4RFaF4V%L5T0F5A6BPart AHow big is the pulling force?Express your answer with the appropriate units.► View Available Hint(s)F=Part BYSubmitFOSubmitProvide FeedbackB = ValueWhat is the strength of the magnetic field?Express your answer with the appropriate units.► View Available Hint(s)HValue&7μÀμÅ←F7NU38JC FO ?UnitsUnitsDIIFB1MPwC ?10.9KDF9O30aF10LP4F11+F12

The length of the wire is The resistance of the wire is The speed of the wire is The power…

A 8.00-cm-long wire is pulled along a U-shaped conducting rail in a perpendicular magnetic field. The total resistance of the wire and rail is 0.340 S2. Pulling the wire at a steady speed of v=4.00 m/s causes 4.30 W of power to be dissipated in the circuit. Y Part A How big is the pulling force? Express your answer with the appropriate units. ▸ View Available Hint(s) F= Value Submit Part B HÅ What is the strength of the magnetic field? Express your answer with the appropriate units. ▸ View Available Hint(s) B= Value Submit Provide Feedback HÅ Units Units ?

A 8.00-cm-long wire is pulled along a U-shaped conducting rail in a perpendicular magnetic field. The total resistance of the wire and rail is 0.340 S2. Pulling the wire at a steady speed of v=4.00 m/s causes 4.30 W of power to be dissipated in the circuit. Y Part A How big is the pulling force? Express your answer with the appropriate units. ▸ View Available Hint(s) F= Value Submit Part B HÅ What is the strength of the magnetic field? Express your answer with the appropriate units. ▸ View Available Hint(s) B= Value Submit Provide Feedback HÅ Units Units ?

Physics for Scientists and Engineers with Modern Physics

10th Edition

ISBN:9781337553292

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter28: Magnetic Fields

Section: Chapter Questions

Problem 26P: Consider the system pictured in Figure P28.26. A 15.0-cm horizontal wire of mass 15.0 g is placed...

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Review. Rail guns have been suggested for launching projectiles into space without chemical rockets. A tabletop model rail gun (Fig. P22.76) consists of two long, parallel, horizontal rails = 3.50 cm apart, bridged by a bar of mass m = 3.00 g that is free to slide without friction. The rails and bar have low electric resistance, and the current is limited to a constant I = 24.0 A by a power supply that is far to the left of the figure, so it has no magnetic effect on the bar. Figure P22.76 shows the bar at rest at the midpoint of the rails at the moment the current is established. We wish to find the speed with which the bar leaves the rails after being released from the midpoint of the rails. (a) Find the magnitude of the magnetic field at a distance of 1.75 cm from a single long wire carrying a current of 2.40 A. (b) For purposes of evaluating the magnetic field, model the rails as infinitely long. Using the result of part (a), find the magnitude and direction of the magnetic field at the midpoint of the bar. (c) Argue that this value of the field will be the same at all positions of the bar to the right of the midpoint of the rails. At other points along the bar, the field is in the same direction as at the midpoint, but is larger in magnitude. Assume the average effective magnetic field along the bar is five times larger than the field at the midpoint. With this assumption, find (d) the magnitude and (e) the direction of the force on the bar. (f) Is the bar properly modeled as a particle under constant acceleration? (g) Find the velocity of the bar after it has traveled a distance d = 130 cm to the end of the rails. Figure P22.76
In Figure P20.65 the rolling axle of length 1.50 m is pushed along horizontal rails at a constant speed v = 3.00 m/s. A resist or R = 0.400 is connected to the rails at points a and b, directly opposite each other. (The wheels make good electrical contact with the rails, so the axle, rails, and R form a closed-loop circuit. The only significant resistance in the circuit is R.) A uniform magnetic field B = 0.800 T is directed vertically downward. (a) Find the induced current I in the resistor. (b) What horizontal force F is required to keep the axle rolling at constant speed? (c) Which end of the resistor, a or b. is at the higher electric potential? (d) Alter the axle rolls past the resistor, does the current in R reverse direction? Explain your answer. Figure P20.65
Is Ampere’s law valid for all closed paths? Why isn’t it normally useful for calculating a magnetic field?
Is the work required to accelerate a rod from rest to a speed v in a magnetic field greater than the final kinetic energy of the rod? Why?
The cross-sectional dimensions of the copper strip shown are 2.0 cm by 2.0 mm. The strip carries a current of 100 A, and it is placed in a magnetic field of magnitude B = 1.5 T. What are the value and polarity of the Hall potential in the copper strip?
Two frictionless conducting rails separated by l = 55.0 cm are connected through a 2.00- resistor, and the circuit is completed by a bar that is free to slide on the rails (Fig. P32.71). A uniform magnetic field of 5.00 T directed out of the page permeates the region, a. What is the magnitude of the force Fp that must be applied so that the bar moves with a constant speed of 1.25 m/s to the right? b. What is the rate at which energy is dissipated through the 2.00- resistor in the circuit?
, A proton, deuteron, and an alpha-particle ae all accelerated from rest through the same potential difference. They then enter the same magnetic field, moving perpendicular to it. Compute the ratios of the radii of their circular paths. Assume that md= 2wmp and ma= 4mp.
A current of 1.5 A flows through the windings of a large, thin toroid with 200 turns per meter. If the toroid is filled with iron for which =3.0103 , what is the magnetic field within it?
Why is the following situation impossible? Figure P28.46 shows an experimental technique for altering the direction of travel for a charged particle. A particle of charge q = 1.00 C and mass m = 2.00 1015 kg enters the bottom of the region of uniform magnetic field at speed = 2.00 105 m/s, with a velocity vector perpendicular to the field lines. The magnetic force on the particle causes its direction of travel to change so that it leaves the region of the magnetic field at the top traveling at an angle from its original direction. The magnetic field has magnitude B = 0.400 T and is directed out of the page. The length h of the magnetic field region is 0.110 m. An experimenter performs the technique and measures the angle at which the particles exit the top of the field. She finds that the angles of deviation are exactly as predicted. Figure P28.46