A ball is launched straight up in the air from a height of 7 feet. Its velocity (feet/second) t seconds after launch is given by f(t) = - 32t + 286. The velocity of the ball 5 seconds after launch is feet/second. (Round answer to nearest tenth.)

A ball is launched straight up in the air from a height of 7 feet. Its velocity (feet/second) t seconds after launch is given by f(t) = - 32t + 286. The velocity of the ball 5 seconds after launch is feet/second. (Round answer to nearest tenth.)

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)

6th Edition

ISBN:9781337111348

Author:Bruce Crauder, Benny Evans, Alan Noell

Publisher:Bruce Crauder, Benny Evans, Alan Noell

ChapterP: Prologue: Calculator Arithmetic

Section: Chapter Questions

Problem 34SBE: A Skydiver When a skydiver jumps from an airplane, his downward velocity, in feet per second, before...

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A ball is launched straight up in the air from a height of 7 feet. Its velocity (feet/second) t seconds after launch is given by f(t) = - 32t + 286.
The velocity of the ball 5 seconds after launch is
feet/second.
(Round answer to nearest tenth.)
Inco
/1)
/1)
0/1)
0/1)
0/1)
0/1)

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