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Asked Dec 7, 2019
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A ball is thrown horizontally from the top of a 60.0 m building and lands 100.0 m from the base of the building. How long is the ball in the air?

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Step 1

Here, 

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Given: The height of the building y = 60.0 m The distance between the base of the building and the point where the ball lands a = 100.0 m Formula used: The time t during which the ball is in air is given by the equation of motion y = Uyt + gt?

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Step 2

Thus,&nbs...

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A ball which is thrown horizontally from the top of the building with a velocity u has no component in the vertical direction at the instant of projection. Therefore, the initial vertical velocity uy = 0. Substitute 60.0 m for y, 9.81 m/s² for g in the formula and calculate t. y = Uyt + gt? 60.0 m =(0 m/s)t + (9.81 m/s² )t² 2(60.0 m) t = 9.81 m = 3.497 s

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