This question has several parts that must be completed sequentiallyA ball is thrown upward from the ground with an initial speed of 17.9 m/s; at the same instant, another ball is dropped from a building 11 m high. After how long will the balls be at the same height? We choose upward as the positive vertical direction. After the balls are released, they are both freelyobjects with acceleration a = -g. During the time interval from the moment the two balls are releasethe instant they are at the same height h above the ground, the ball thrown upward undergoes adisplacementAy1 = y - Yo = h 0.%3DThus the displacement equation for constant acceleration Ay = vt +at gives the following equatio1m/s)t-(1)For this same tìme interval, the displacement of the dropped ball isAy2 = y - Yo = h -(and Ay = vt +at? becomes2.m) = (0)t +÷(-g)t2%3Dor(2)

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Description: This question has several parts that must be completed sequentiallyA ball is thrown upward from the ground with an initial speed of 17.9 m/s; at the same instant, another ball is dropped from a building 11 m high. After how long will the balls be at

Given data: Initial velocity of ball is v0=17.9 m/s.

Answered: A ball is thrown upward from the ground…

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A ball is thrown upward from the ground with an initial speed of 17.9 m/s; at the same instant, another ball is dropped from a building 11 m high. After how long will the balls be at the same height?

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter3: Motion Along A Straight Line

Section: Chapter Questions

Problem 113CP: The position of a particle moving along the x -axis varies with time according to x(t)=5.0t24.0t3 ....

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