A ball is thrown upward from the top of a building with a velocity of 14.7 meters / sec. and after reaching its maximum height, it begins to descend in free fall until it reaches the ground (down on the road). If we take the top of the building as a reference: a) Determine the time (tymax-) at which the ball reaches its maximum height and the value of said maximum height (ymax-). b) Determine the position (y) and the velocity (v,) of the ball for a time equal to 2 seconds. For the 2-second time, is the ball above the top of the building or below the top of the building? Is the ball going up or down? c) Determine the position (y) and the velocity (v,) of the ball for a time equal to 4 seconds. For the 4-second time, is the ball above the top of the building or below the top of the building? Is the ball going up or down? d) Determine the velocity (v,) of the ball at a height of 6 meters above the top of the building. Explain your answer in terms of the signs obtained in your result.

College Physics
1st Edition
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:Paul Peter Urone, Roger Hinrichs
Chapter2: Kinematics
Section: Chapter Questions
Problem 54PE: A ball is thrown straight up. It passes a 2.00-m-high window 7.50 m off the ground on its path up...
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A ball is thrown upward from the top of a building with a velocity of 14.7 meters / sec. and after
reaching its maximum height, it begins to descend in free fall until it reaches the ground (down
on the road). If we take the top of the building as a reference:
a) Determine the time (tymax.) at which the ball reaches its maximum height and the value of
said maximum height (ymax-).
b) Determine the position (y) and the velocity (v,) of the ball for a time equal to 2 seconds. For
the 2-second time, is the ball above the top of the building or below the top of the building? Is
the ball going up or down?
c) Determine the position (y) and the velocity (v,) of the ball for a time equal to 4 seconds. For
the 4-second time, is the ball above the top of the building or below the top of the building? Is
the ball going up or down?
d) Determine the velocity (v,) of the ball at a height of 6 meters above the top of the building.
Explain your answer in terms of the signs obtained in your result.
Transcribed Image Text:A ball is thrown upward from the top of a building with a velocity of 14.7 meters / sec. and after reaching its maximum height, it begins to descend in free fall until it reaches the ground (down on the road). If we take the top of the building as a reference: a) Determine the time (tymax.) at which the ball reaches its maximum height and the value of said maximum height (ymax-). b) Determine the position (y) and the velocity (v,) of the ball for a time equal to 2 seconds. For the 2-second time, is the ball above the top of the building or below the top of the building? Is the ball going up or down? c) Determine the position (y) and the velocity (v,) of the ball for a time equal to 4 seconds. For the 4-second time, is the ball above the top of the building or below the top of the building? Is the ball going up or down? d) Determine the velocity (v,) of the ball at a height of 6 meters above the top of the building. Explain your answer in terms of the signs obtained in your result.
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