A ball is tossed from an upper-story window of a building. The ball is given an initial velocity of 8m/s at 20° below the horizontal. It strikes the ground 3s later. (a) How far horizontally from the base of the building does the ball strike the ground? (b)Find the height from which the ball was thrown. (c) How long does it takes the ball to reach a point 10m below the level of launching? (a) x, = vt = (8.00 m/s)cos 20.0° (3.00 s) = 22.6 m Taki

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter3: Motion In Two Dimensions
Section: Chapter Questions
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why is it not -9.8m/s^2?

A ball is tossed from an upper-story window of a building.
The ball is given an initial velocity of 8m/s at 20° below the
horizontal. It strikes the ground 3s later.
(a) How far horizontally from the base of the building does the
ball strike the ground? (b)Find the height from which the ball
was thrown. (c) How long does it takes the ball to reach a point
10m below the level of launching?
(a) x,= v„t = (8.00 m/s)cos 20.0° (3.00 s) = 22.6 m
%3D
(b) Taking y positive downwards,
1
Y; = v„t+
2
y; = (8.00 m/s)sin 20.0° (3.00 s)+÷(9.80 m/s²)(3.00 s)²
= 52.3 m
Transcribed Image Text:A ball is tossed from an upper-story window of a building. The ball is given an initial velocity of 8m/s at 20° below the horizontal. It strikes the ground 3s later. (a) How far horizontally from the base of the building does the ball strike the ground? (b)Find the height from which the ball was thrown. (c) How long does it takes the ball to reach a point 10m below the level of launching? (a) x,= v„t = (8.00 m/s)cos 20.0° (3.00 s) = 22.6 m %3D (b) Taking y positive downwards, 1 Y; = v„t+ 2 y; = (8.00 m/s)sin 20.0° (3.00 s)+÷(9.80 m/s²)(3.00 s)² = 52.3 m
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