A ball (m-2.5 kg) on a string is being swung in a vertical circle of radius 1.20 m, asshown. Its speed at the top is 4.00 m/sVr = 4.00 m/s (d) When the ball is at the top of the swing, what is the magnitude of theacceleration of the ball?23.1 m/s^29.81 m/s^213.3 m/s 233.3 m/s^2

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Answered: A ball (m-2.5 kg) on a string is being…

A ball (m-2.5 kg) on a string is being swung in a vertical circle of radius 1.20 m, as shown. Its speed at the top is 4.00 m/s Vr = 4.00 m/s

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter5: More Applications Of Newton’s Laws

Section: Chapter Questions

Problem 35P

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Concept explainers

Centripetal Force

A particle, body, object or certain mass while travelling in a rotational path or semicircular path, experiences an inertia force. If that inertia force pulls the towards the inward of the imaginary circle in the rotation, it is termed as centripetal force.

Question

A ball (m-2.5 kg) on a string is being swung in a vertical circle of radius 1.20 m, as
shown. Its speed at the top is 4.00 m/s
Vr = 4.00 m/s

(d) When the ball is at the top of the swing, what is the magnitude of the
acceleration of the ball?
23.1 m/s^2
9.81 m/s^2
13.3 m/s 2
33.3 m/s^2

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