A bar of circular cross section is subjected to point loads of P1, P2, P3 and P4 as shown here. Find the magnitude of the force P3 necessary for the equilibrium, if P1= 110 kN, P2 = 240 kN & P4 = 190 kN. Also, determine the stresses in each section & the net change in the length of steel bar. where d1=70mm, L1=33 cm, d2 = 30mm, L2=39 cm, d3=70 mm & L3 =34 cm. Take E = 174 GPa. d2 d1 →P2 P3 + d3 P1 P4 L1 L2 L3 The force P3 to make it to equilibrium in kN is The Stress in section 1 in N/mm² is The Compressive Stress in section 2 in N/mm2 is

Mechanics of Materials (MindTap Course List)
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Author:Barry J. Goodno, James M. Gere
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Chapter1: Tension, Compression, And Shear
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A bar of circular cross section is subjected to point loads of P1, P2, P3 and P4 as shown here. Find the magnitude of
the force P3 necessary for the equilibrium, if P1= 110 kN, P2 = 240 kN & P4 = 190 kN. Also, determine the stresses in
each section & the net change in the length of steel bar. where d1=70mm, L1=33 cm, d2 = 30mm, L2=39 cm,
d3=70 mm & L3 =34 cm. Take E = 174 GPa.
d2
d1
→P2
P3
d3
P1
P4
L1
L2
L3
The force P3 to make it to equilibrium in kN is
The Stress in section 1 in N/mm2 is
The Compressive Stress in section 2 in N/mm2 is
Transcribed Image Text:A bar of circular cross section is subjected to point loads of P1, P2, P3 and P4 as shown here. Find the magnitude of the force P3 necessary for the equilibrium, if P1= 110 kN, P2 = 240 kN & P4 = 190 kN. Also, determine the stresses in each section & the net change in the length of steel bar. where d1=70mm, L1=33 cm, d2 = 30mm, L2=39 cm, d3=70 mm & L3 =34 cm. Take E = 174 GPa. d2 d1 →P2 P3 d3 P1 P4 L1 L2 L3 The force P3 to make it to equilibrium in kN is The Stress in section 1 in N/mm2 is The Compressive Stress in section 2 in N/mm2 is
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