A block of mass m = 10.5 kg rests on an inclined plane with a coefficient of staticfriction of us = 0.055 between the block and the plane. The inclined plane is L = 6.8 m long and it has aheight of h = 3.8 m at its tallest point.) What angle, in degrees, does the plane make with respect to the horizontal?b) What is the magnitude of the normal force, Fy in newtons, that acts on the block?0mL→Xc) What is the component of the force of gravity along the plane, Fex in newtons?gxd) Write an expression, in terms of 0, the mass m, the coefficient of static friction us, and the gravitational constant g, for the magnitude of the forcedue to static friction, F, just before the block begins to slide.(e) Will the block slide?

Name: A block of mass m = 10.5 kg rests on an inclined plane with a coeffic
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Description: A block of mass m = 10.5 kg rests on an inclined plane with a coefficient of staticfriction of us = 0.055 between the block and the plane. The inclined plane is L = 6.8 m long and it has aheight of h = 3.8 m at its tallest point.) What angle, in deg

Given data:Mass of the block: Coefficient of static friction: Length of the inclined plane: Height…

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A block of mass m = 10.5 kg rests on an inclined plane with a coefficient of static of us = 0.055 between the block and the plane. The inclined plane is L= 6.8 m long and it has a friction height of h= 3.8 m at its tallest point. ) What angle, 0 in degrees, does the plane make with respect to the horizontal? b) What is the magnitude of the normal force, Fy in newtons, that acts on the block? m e) What is the component of the force of gravity along the plane, Fgx in newtons? d) Write an expression, in terms of 0, the mass m, the coefficient of static friction us, and the gravitational constant g, for the magnitude of the force due to static friction, F,, just before the block begins to slide. (e) Will the block slide?

A block of mass m = 10.5 kg rests on an inclined plane with a coefficient of static of us = 0.055 between the block and the plane. The inclined plane is L= 6.8 m long and it has a friction height of h= 3.8 m at its tallest point. ) What angle, 0 in degrees, does the plane make with respect to the horizontal? b) What is the magnitude of the normal force, Fy in newtons, that acts on the block? m e) What is the component of the force of gravity along the plane, Fgx in newtons? d) Write an expression, in terms of 0, the mass m, the coefficient of static friction us, and the gravitational constant g, for the magnitude of the force due to static friction, F,, just before the block begins to slide. (e) Will the block slide?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Newton's Second Law

Newton’s laws of motion describe the relationship between the motion of an object and forces acting on it. Newton’s law of motion has two types as follows:

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A block of mass m = 10.5 kg rests on an inclined plane with a coefficient of static
friction of us = 0.055 between the block and the plane. The inclined plane is L = 6.8 m long and it has a
height of h = 3.8 m at its tallest point.
) What angle, in degrees, does the plane make with respect to the horizontal?
b) What is the magnitude of the normal force, Fy in newtons, that acts on the block?
0
m
L
→X
c) What is the component of the force of gravity along the plane, Fex in newtons?
gx
d) Write an expression, in terms of 0, the mass m, the coefficient of static friction us, and the gravitational constant g, for the magnitude of the force
due to static friction, F, just before the block begins to slide.
(e) Will the block slide?

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Step 1: Given data and concept:

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Step 2: a) Angle of the plane with respect to the horizontal:

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Step 3: b) Magnitude of the normal force:

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Step 4: c) Component of the force of gravity along the plane:

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Step 5: d) Expression for the force due to static friction:

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Step 6: e) Checking, whether the block will slide:

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