Question
Asked Oct 9, 2019
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A block of wood of mass 2.6 kg is moved up along 8.9 m incline from rest by applying a
horizontal force of 25 N. If the incline makes an angle of 23 with the horizontal and the
total work done on block to move it up the is 78.9 J, calculate the magnitude of frictional
force between wood and the incline.
(a) 4.19 N
(b) 15.5 N
(c) 12.6 N
(d) 6.79 N
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A block of wood of mass 2.6 kg is moved up along 8.9 m incline from rest by applying a horizontal force of 25 N. If the incline makes an angle of 23 with the horizontal and the total work done on block to move it up the is 78.9 J, calculate the magnitude of frictional force between wood and the incline. (a) 4.19 N (b) 15.5 N (c) 12.6 N (d) 6.79 N

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Expert Answer

Step 1

Consider the free body diagram shown below.

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m-2.6kg AC = 8-9m F25N F -23 AC Sine A

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Step 2

The total work done on the block is the sum of work done by horizontal component ...

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W =work done by F +work done by gravity + work done by friction =(Fcos)AC -mgh-fx AC (Fcos0)AC -mg (AC sin 0)- fx AC

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