- A boat moves through the water with two forces acting on it. One is a 1,875-N forward push by the water on the propeller, and the other is a 1,400-N resistive force due to the water around the bow.(a) What is the acceleration of the 1,100-kg boat?(b) If it starts from rest, how far will the boat move in 17.5 s?(c) What will its velocity be at the end of that time?

Question
Asked Nov 1, 2019
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- A boat moves through the water with two forces acting on it. One is a 1,875-N forward push by the water on the propeller, and the other is a 1,400-N resistive force due to the water around the bow.

(a) What is the acceleration of the 1,100-kg boat?

(b) If it starts from rest, how far will the boat move in 17.5 s?

(c) What will its velocity be at the end of that time?

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Expert Answer

Step 1

Consider two opposite forces are acting on the boat given by  Fforward and Fresistive and their magnitudes are 1875 N and 1400 N respectively.

(a)  Write newton’s second law and plug the required values to find the acceleration of the both, (given mass, m of the boat is 1100 kg).

>F ma
net
F
forward
-Fresistive ma
- F
resistive
F
forward
a =
т
(1875 N)-(1400 N)
а -
(1100 kg)
a 0.43 m/s2
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Image Transcriptionclose

>F ma net F forward -Fresistive ma - F resistive F forward a = т (1875 N)-(1400 N) а - (1100 kg) a 0.43 m/s2

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Step 2

(b) Consider boat starts from rest(that is, u=0 m/s), write the motion’s equation and plug t...

1
S = ut
2
=(0 m/s)(17.5 s)+(0.43 m/s)(17.5 s)
2
65.84 m
help_outline

Image Transcriptionclose

1 S = ut 2 =(0 m/s)(17.5 s)+(0.43 m/s)(17.5 s) 2 65.84 m

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