A boat moves through the water with two forces acting on it. One is a 1,950-N forward push by the water on the propeller, and the other is a 1,300-N resistive force due to the water around the bow.(a) What is the acceleration of the 1,200-kg boat?m/s 2(b) If it starts from rest, how far will the boat move in 25.0 s?(c) What will its velocity be at the end of that time?m/sNeed Help?Read It

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Description: A boat moves through the water with two forces acting on it. One is a 1,950-N forward push by the water on the propeller, and the other is a 1,300-N resistive force due to the water around the bow.(a) What is the acceleration of the 1,200-kg boat?m/

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Principles of Physics: A Calculus-Based Text

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Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter5: More Applications Of Newton’s Laws

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A boat moves through the water with two forces acting on it. One is a 1,950-N forward push by the water on the propeller, and the other is a 1,300-N resistive force due to the water around the bow.
(a) What is the acceleration of the 1,200-kg boat?
m/s 2
(b) If it starts from rest, how far will the boat move in 25.0 s?
(c) What will its velocity be at the end of that time?
m/s
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Expert Solution

Step 1

Given,

force on boat F= 1990 N

restive force on boat f= 1300 N

Mass of the boat is m = 1200 Kg

(a)

We know the expression for force is

$F_{net} = ma 1950 - 1300 = 1200 \times a a = \frac{650}{1200} a = 0.54 m / s^{2}$

Therefore the acceleration on the boat is 0.54 m/s²

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