A body moving on a frictionless horizontal surface with some initial velocity encounters a section of rough surface. It takes the body several seconds to traverse the rough section. During this time the momentum of the body will   (A) increase due to the force of friction that supplies an impulse to the body. (B) decrease due to the force of friction that supplies a retarding impulse to the body.     (C) remain constant since the only force acting on the body as it crosses the rough surface is friction. (D) change in both magnitude and direction since the rough surface supplies a force opposite to the direction of motion for some time interval that will reverse its motion.

Q: Two objects, both with a mass of 1.87 kg are sliding across a horizontal, frictionless surface…

A:

Q: Two objects, both with a mass of 1.89 kg are sliding across a horizontal, frictionless surface…

A: given: m1=m2=1.89 kg v1 = 4.99 i m/s v2 = -2.16 i m/s let final velocity= v

Q: An elephant with a mass 2930 kg is running with a speed of 32.3 km/h, and a cheetah with a mass of…

A:

Q: A soccer ball with a mass of 0.426 kg approaches a player horizontally with a speed of 16.0 m/s. The…

A: The given values are,

Q: Consider a collision between a more massive object and a less massive object. Which one of the…

A:

Q: A bullet of mass 200 g traveling horizontally with a speed of 319 m/s. It strikes a block of mass…

A: From the momentum conservation, Here, mb, m, ub, u and v represent the mass of a bullet, the…

Q: A volleyball with a mass of 0.267 kg approaches a player horizontally with a speed of 13.0 m/s. The…

A: Given data : The mass of volleyball is, m = 0.267 kg. Approaching speed of volleyball to player is,…

Q: A baseball of mass m = 0.26 kg is dropped from a height h1 = 2.05 m. It bounces from the concrete…

A: V1= 2gh1= 2×9.81×2.05= 6.342 m/sV2= 2gh2= 2×9.81×1.63 = 5.655 m/s

Q: A 2.4-kg ball falling vertically hits the floor with a speed of 2.5 m/s and rebounds with a speed of…

A: Given data: Mass of the ball (m) = 2.4 kg Downward speed of the ball (v1) = 2.5 m/s Rebound upward…

Q: A 1.2 kg ball is falling in the -y direction at a speed of 25 m/s. The ball strikes the floor and…

A: The expression for find impulse acts on the ball is J=mvf-vi

Q: A particle with a mass of 1.55 kg is acted on by a force Fx acting in the x-direction. If the…

A:

Q: A 0.188 kg baseball, thrown with a speed of 44.3 m/s, is hit straight back at the pitcher with a…

A:

Q: A particle is moving along the x axis, and the graph shows its momentum p as a function of time t.…

A: Force is given as the rate of change of momentum with time. So, the slope of the graph represents…

Q: In the overhead view of the figure, a 440 g ball with a speed v of 3.8 m/s strikes a wall at an…

A: Given: mas, m = 440 g = 0.44 kg  velocity,u = 3.8 m/s  v = 3.8 m/s  t = 5.8 ms = 0.0058 s θ = 22°

Q: A 65.1-kg basketball player jumps vertically and leaves the floor with a velocity of 1.96 m/s…

A: Given mass m = 65.1 kg initial velocity u = 0 m/s final velocity v = 1.96 m/s

Q: A particle with a mass of 2.80 kg is acted on by a force F, acting in the x-direction. If the…

A: a. the area under Ft graph is equal to the impulse. Then

Q: In a common but dangerous prank, a chair is pulled away as a person is moving downward to sit on it,…

A:

Q: A golf ball m = 0.195 kg strikes a vertical concrete wall elastically with a horizontal velocity of…

A: The mass of the golf ball is m = 0.195 kg. The elastically horizontal velocity of the golf ball is…

Q: ollowing scenarios describes impulse? A. Two cars collide with one another. B. An airplane…

A: IMPULSE:-  We know that the impulse is defined as the force and change in time.  Impulse = F∆twhere…

Q: A soccer player kicks a soccer ball of mass 0.45 kg that is initially at rest. The player's foot is…

A: mass of ball (m) = 0.45 kg t = 1.60×10-3 seconds Force is given by : F(t) = 7.52×105×t - (4.7×108)t2…

Q: A 0.149 kg baseball, thrown with a speed of 39.5 m/s, is hit straight back at the pitcher with a…

A: (a)According to the impulse-momentum theorem, the impulse delivered to the baseball must be equal to…

Q: A soccer player kicks a soccer ball of mass 0.45 kg that is initially at rest. The player's foot is…

A:

Q: A 0.150-kg baseball, thrown with a speed of 40.0 m/s, is hit straight back at the pitcher with a…

A: Given data:  Mass of baseball (m) = 0.150 kg Initial velocity (Vi) = - 40.0 m/s Final velocity (Vf)…

Q: In the overhead view of the figure, a 480 g ball with a speed v of 8.6 m/s strikes a wall at an…

A: (a)  J →= Δp→Δp→ = m(v→f-v→i)Here, v→i = +8.22i^-2.5j^v→f = +8.22i^+2.5j^J →= (0.48kg x 5…

Q: 5-kg cart moving with a velocity v1i = 2.25 m/s collides elastically with a second cart of mass 5.75…

A: Given values:- Mass of First cart,(m1)=1.25 kg ----(1) Velocity of First cart,(v1)=2.25 m/sec…

Q: Two objects, both with a mass of 1.87 kg are sliding across a horizontal, frictionless surface…

A: Given: The mass of the object is 1.87 kg. The initial velocity of the first object is 4.63 m/si. The…

Q: A soccer ball with a mass of 0.427 kg approaches a player horizontally with a speed of 16.0 m/s. The…

A: The magnitude of impulse can be obtained as Impulse=∆p=mvf-vi=0.427kg22.6m/s--16.0m/s=16.48 kgm/s

Q: A particle with a mass of 1.40 kg is acted on by a force Fx acting in the x-direction. If the…

A: (a)   The impulse of the force can be determined by the area below the graph as below.

Q: by a rope along a horizontal surface with negligible friction. For time t > 0, the magnitude of the…

A: We know that the impulse is given as  J = Fdt  We also know that by the newton second law of motion…

Q: The vector position of a 3.50-g particle moving in the xy plane varies in time according to r→1 =…

A: Hai, since there are multiple sub parts posted, we will answer the first three sub parts. (a)

Q: A shell at rest explodes into two fragments, one with a mass of im1 = 2.0 kg and the other m2 = 5.0…

A: It is given that m1=2 kgm2=5 kgK2=100 Ju=0

Q: A block of mass m is pulled by a rope along a horizontal surface with negligible friction. For time…

A: Given,

Q: A soccer ball with a mass of 0.427 kg approaches a player horizontally with a speed of 14.0 m/s. The…

A: Given data:  Mass (m) = 0.427 kg Initial speed = 14.0 m/s, towards player Final speed = 22.3 m/s, in…

Q: Which of the following statement is not true about impulse?         a. It is applied to change the…

A: Impulse is defined as the product of Force and the time for which it acts. Mathematically, Impulse =…

Q: In the overhead view of the figure, a 460 g ball with a speed v of 4.5 m/s strikes a wall at an…

A: Find the impulse acting on the ball and average force exerted on the ball.

Q: In what way can you tell if linear momentum and/or k.E are conserved in a 1D collision? Would the…

A:

Q: Two objects, both with a mass of 1.92 kg are sliding across a horizontal, frictionless surface…

A:

Q: 120 100 80 60 40 20 10 20 30 40 50 time /s

A: Given Data: Mass of the particle is m = 1.9 kg. Part (a) Impulse in force and time diagram is the…

Q: Consider the collision of a moving puck with a second, initially stationary puck, as shown in the…

A: Given: m1=0.50 kgm2=0.60 kgv1=1.5 m/sv1f=0.5 m/sθ1=50°

Q: Object A with mass 520 g and traveling rightward at 0.8 m/s collides head on with Object B with mass…

A:

Q: A particle with a mass of 1.25 kg is acted on by a force F acting in the x-direction. If the…

A: a) The expression for calculate the impulse of the force is j=F×∆t Substitute values in the above…

Q: In a common but dangerous prank, a chair is pulled away as a person is moving downward to sit on it,…

A:

Q: F (N) 4 3 1 t (s) 4 5 1 3 The magnitude of the net force exerted in the x direction on a 2.5 kg…

A:

Q: Problem 7.1

A: Given, Mass of particle A , mA = 2.8 kg Mass of particle B , mB = 5.6 kg Velocity of particle A , vA…

Q: A soccer player kicks a soccer ball of mass 0.45 kg that is initially at rest. The player's foot is…

A:

Q: Before In a crash test, a car of mass 1500 kg collides with a wall and rebounds as in the figure.…

A: The relationship of impulse and momentum is, I=m∆v I=1500(15-2.6) I=18600 kg m/s

Q: The total momentum of a system is conserved if the only forces of interaction regarding the objects…

A: