A bottle of juice with a temperature of 95°F was taken off a shelf and placed in a cooling unit with an internal temperature of 30°F. After ten minutes, the internal temperature of the juice was 80°F. Therefore our model would be: T(t) = 65e-0.026t + 30. To the nearest degree, what will the temperature of the juice be after 40 minutes? Do not enter "F" in the answer box.

Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter6: Vector Spaces
Section6.7: Applications
Problem 13EQ
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QUESTION 11
A bottle of juice with a temperature of 95°F was taken off a shelf and placed in a cooling unit with an internal temperature of 30°F. After ten minutes, the internal temperature of the juice was
80°F. Therefore our model would be: T(t) = 65e0.026t + 30. To the nearest degree, what will the temperature of the juice be after 40 minutes? Do not enter "°F" in the answer box.
Transcribed Image Text:QUESTION 11 A bottle of juice with a temperature of 95°F was taken off a shelf and placed in a cooling unit with an internal temperature of 30°F. After ten minutes, the internal temperature of the juice was 80°F. Therefore our model would be: T(t) = 65e0.026t + 30. To the nearest degree, what will the temperature of the juice be after 40 minutes? Do not enter "°F" in the answer box.
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