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A box of mass M slides down a ramp at constant speed. The coefficient of kinetic and static friction between the box and ramp are µk and µs respectively. What condition will be true at the angle if the block slides down the ramp at a constant speed? Don't guess. Use the free body diagram method with a tilted coordinate system. O HKFN = Mg sin e with FN = Mg O Hk FN = Mg sin 0 with FN = Mg cos 0 O Hs FN = Mg sin 0 with FN = Mg O HSFN = Mg cos 0 with FN = Mg O Hk FN = Mg cos 0 with FN = Mg sin 0 O HsFN = Mg sin 0 with FN = Mg cos 0 O Hs FN = Mg cos 0 with FN = Mg sin 0 O Hk FN = Mg cos 0 with FN = Mg

A box of mass M slides down a ramp at constant speed. The coefficient of kinetic and static friction between the box and ramp are µk and µs respectively. What condition will be true at the angle if the block slides down the ramp at a constant speed? Don't guess. Use the free body diagram method with a tilted coordinate system. O HKFN = Mg sin e with FN = Mg O Hk FN = Mg sin 0 with FN = Mg cos 0 O Hs FN = Mg sin 0 with FN = Mg O HSFN = Mg cos 0 with FN = Mg O Hk FN = Mg cos 0 with FN = Mg sin 0 O HsFN = Mg sin 0 with FN = Mg cos 0 O Hs FN = Mg cos 0 with FN = Mg sin 0 O Hk FN = Mg cos 0 with FN = Mg

Principles of Physics: A Calculus-Based Text
Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter5: More Applications Of Newton’s Laws
Section: Chapter Questions
Problem 14P: Three objects are connected on a table as shown in Figure P5.14. The coefficient of kinetic friction...
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A box of mass M slides down a ramp at constant speed. The coefficient of kinetic and static friction between the box and ramp are uk and us respectively. What condition will be true at the angle if the block slides down the ramp at a constant speed? Don't guess. Use the free body diagram method with a tilted coordinate system. O HKFN = Mg sin 0 with FN = Mg O HKFN = Mg sin 0 with FN = Mg cos 0 O HsFN = Mg sin 0 with FN = Mg O HFN = Mg cos 0 with FN = Mg O HKFN = Mg cos O with FN = Mg sin 0 O HSFN = Mg sin 0 with FN = Mg cos 0 O HsFN = Mg cos 0 with FN = Mg sin 0 O HKFN = Mg cos O with FN = Mg
Transcribed Image Text:A box of mass M slides down a ramp at constant speed. The coefficient of kinetic and static friction between the box and ramp are uk and us respectively. What condition will be true at the angle if the block slides down the ramp at a constant speed? Don't guess. Use the free body diagram method with a tilted coordinate system. O HKFN = Mg sin 0 with FN = Mg O HKFN = Mg sin 0 with FN = Mg cos 0 O HsFN = Mg sin 0 with FN = Mg O HFN = Mg cos 0 with FN = Mg O HKFN = Mg cos O with FN = Mg sin 0 O HSFN = Mg sin 0 with FN = Mg cos 0 O HsFN = Mg cos 0 with FN = Mg sin 0 O HKFN = Mg cos O with FN = Mg
A box of mass M slides down a ramp with the angle of 0 as shown. What is the kinetic friction force on the box? The coefficient of kinetic friction is µk. Don't guess. Use the free body diagram method with a tilted coordinate system. O HkMg sin 0 down ramp O HyMg cos 0 up ramp O HKMg down ramp O HyMg cos 0 down ramp O HKMg up ramp O HyMg sin 0 up ramp
Transcribed Image Text:A box of mass M slides down a ramp with the angle of 0 as shown. What is the kinetic friction force on the box? The coefficient of kinetic friction is µk. Don't guess. Use the free body diagram method with a tilted coordinate system. O HkMg sin 0 down ramp O HyMg cos 0 up ramp O HKMg down ramp O HyMg cos 0 down ramp O HKMg up ramp O HyMg sin 0 up ramp
Expert Solution
Step 1

Given data

The mass of the box is M

The angle of inclination is θ

The coefficient of kinetic friction is μk

The coefficient of static friction is μs

 

The free-body diagram of the configuration is shown below:

Physics homework question answer, step 1, image 1

The expression for the normal reaction force is given as:

FN=Mgcosθ

The expression for the  force in the inclined position is given as:

Ff=Mgsinθ

The friction force is given as:

Ff=μkFNμkFN=Mgsinθ

Thus, the friction force is shown above.

 

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