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A box with a square base and open top must have a volume of 237276 cm*. We wish to find the dimensions of the box that minimize the amount of material used. First, find a formula for the surface area of the box in terms of only a, the length of one side of the square base. [Hint: use the volume formula to express the height of the box in terms of æ.] Simplify your formula as much as possible. A(x) = | Next, find the derivative, A'(x). A'(교) = | Now, calculate when the derivative equals zero, that is, when A'(x) = 0. [Hint: multiply both sides by æ.] A' (x) = 0 when a = We next have to make sure that this value of æ gives a minimum value for the surface area. Let's use the second derivative test. Find A"(x). A"(x) = | Evaluate A"(x) at the x-value you gave above. NOTE: Since your last answer is positive, this means that the graph of A(x) is concave up around that value, so the zero of A' (x) must indicate a local minimum for A(x). (Your boss is happy now.)

A box with a square base and open top must have a volume of 237276 cm*. We wish to find the dimensions of the box that minimize the amount of material used. First, find a formula for the surface area of the box in terms of only a, the length of one side of the square base. [Hint: use the volume formula to express the height of the box in terms of æ.] Simplify your formula as much as possible. A(x) = | Next, find the derivative, A'(x). A'(교) = | Now, calculate when the derivative equals zero, that is, when A'(x) = 0. [Hint: multiply both sides by æ.] A' (x) = 0 when a = We next have to make sure that this value of æ gives a minimum value for the surface area. Let's use the second derivative test. Find A"(x). A"(x) = | Evaluate A"(x) at the x-value you gave above. NOTE: Since your last answer is positive, this means that the graph of A(x) is concave up around that value, so the zero of A' (x) must indicate a local minimum for A(x). (Your boss is happy now.)

Mathematics For Machine Technology
Mathematics For Machine Technology
8th Edition
ISBN:9781337798310
Author:Peterson, John.
Publisher:Peterson, John.
Chapter63: Volumes Of Pyramids And Cones
Section: Chapter Questions
Problem 16A: A piece in the shape of a pyramid with a regular octagon (eight sided) base is machined from a solid...
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A box with a square base and open top must have a volume of 237276 cm*. We wish to find the dimensions of the box that minimize the amount of material used. First, find a formula for the surface area of the box in terms of only a, the length of one side of the square base. [Hint: use the volume formula to express the height of the box in terms of æ.] Simplify your formula as much as possible. A(z) = Next, find the derivative, A'(x). A'(x) = Now, calculate when the derivative equals zero, that is, when A'(x) = 0. [Hint: multiply both sides by a?.] A'(x) = 0 when x = We next have to make sure that this value of æ gives a minimum value for the surface area. Let's use the second derivative test. Find A"(x). A"(x) =| Evaluate A"(x) at the r-value you gave above. NOTE: Since your last answer is positive, this means that the graph of A(a) is concave up around that value, so the zero of A'(x) must indicate a local minimum for A(x). (Your boss is happy now.)
Transcribed Image Text:A box with a square base and open top must have a volume of 237276 cm*. We wish to find the dimensions of the box that minimize the amount of material used. First, find a formula for the surface area of the box in terms of only a, the length of one side of the square base. [Hint: use the volume formula to express the height of the box in terms of æ.] Simplify your formula as much as possible. A(z) = Next, find the derivative, A'(x). A'(x) = Now, calculate when the derivative equals zero, that is, when A'(x) = 0. [Hint: multiply both sides by a?.] A'(x) = 0 when x = We next have to make sure that this value of æ gives a minimum value for the surface area. Let's use the second derivative test. Find A"(x). A"(x) =| Evaluate A"(x) at the r-value you gave above. NOTE: Since your last answer is positive, this means that the graph of A(a) is concave up around that value, so the zero of A'(x) must indicate a local minimum for A(x). (Your boss is happy now.)
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