Can you box the answers please - Part 1: Find the surface area of the open box as a function of x and h, where x represents the length of the sides of the square baseand h the height of the open box.A(x, h) = x^2+4xh- Part 2: Find the volume of the open box as a function of x and h.V(x, h) =Part 3: Find the value of h as a function of x, using the given value of the volume.Part 4: Rewrite the surface area of the open box as a function of x only.Part 5: Find the derivative of the surface area of the open box with respect to x.Part 6: Find the height and length values that minimize the surface area of the open box. A box with an open top has vertical sides, asquare bottom and a volume of 4 cubicmeters. If the box has the least possiblesurface area find its dimensions.First the surface area of the open box as afunction of x and h where x represents thelength of the sides of the squares base and hthe height of the open box.

The base of the box is a square with side length x. The height of the box is given as h. The Surface…

A box with an open top has vertical sides, a square bottom and a volume of 4 cubic meters. If the box has the least possible surface area find its dimensions. First the surface area of the open box as a function of x and h where x represents the length of the sides of the squares base and h the height of the open box.