A bronze pipe (1) is to be connected to an aluminum alloy pipe (2) at flange B. When put in place, however, a gap of A = 0.20 in. existsbetween the two pipes. Bronze pipe (1) has an elastic modulus of E, = 16,000 ksi, a cross-sectional area of A, = 2.30 in.?, and a lengthof L1 = 3.3 ft. Aluminum alloy pipe (2) has an elastic modulus of E2 = 10,000 ksi, a cross-sectional area of A2 = 1.21 in.2, and a length ofL2 = 10.5 ft. If bolts are inserted in the flanges and tightened so that the gap at B is closed, determine:(a) the normal stresses produced in each of the members.(b) the final position of flange B with respect to support A.%3D%3DL1L2B(1)(2)Answer:(a) σ1-ksi02 =ksi(b) 8B/Ain.Save for LaterAttempts: 0 of 1 usedSubmit Answer

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A bronze pipe (1) is to be connected to an aluminum alloy pipe (2) at flange B. When put in place, however, a gap of A = 0.20 in. exists between the two pipes. Bronze pipe (1) has an elastic modulus of E, = 16,000 ksi, a cross-sectional area of A, = 2.30 in.2, and a length of L1 = 3.3 ft. Aluminum alloy pipe (2) has an elastic modulus of E2 = 10,000 ksi, a cross-sectional area of A2 = 1.21 in.?, and a length of L2 = 10.5 ft. If bolts are inserted in the flanges and tightened so that the gap at B is closed, determine: (a) the normal stresses produced in each of the members. (b) the final position of flange B with respect to support A. L2 B A (2) (1) Answer: (a) 01 = ksi 02 = ksi (b) 8B/A = in. Save for Later Attempts: 0 of 1 used Submit Answer

A bronze pipe (1) is to be connected to an aluminum alloy pipe (2) at flange B. When put in place, however, a gap of A = 0.20 in. exists between the two pipes. Bronze pipe (1) has an elastic modulus of E, = 16,000 ksi, a cross-sectional area of A, = 2.30 in.2, and a length of L1 = 3.3 ft. Aluminum alloy pipe (2) has an elastic modulus of E2 = 10,000 ksi, a cross-sectional area of A2 = 1.21 in.?, and a length of L2 = 10.5 ft. If bolts are inserted in the flanges and tightened so that the gap at B is closed, determine: (a) the normal stresses produced in each of the members. (b) the final position of flange B with respect to support A. L2 B A (2) (1) Answer: (a) 01 = ksi 02 = ksi (b) 8B/A = in. Save for Later Attempts: 0 of 1 used Submit Answer

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter11: Columns

Section: Chapter Questions

Problem 11.5.7P: Solve the preceding problem for a column with e = 0.20 in,, L = 12 ft, I = 2L7in4, and E = 30 ×...

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