A bungee jumping company wants to set up a bungee jumping location on the top of a bridge that is 300 m above the ground. For safety reasons, the company wants to select a bungee cord spring constant such that a jumper with a mass of 115 kg will reach his lowest point – that is, the point when the change in gravitational potential energy equals the amount of energy stored in the bungee cord at the bottom of the jump at 50 m above the ground. What is the approximate spring constant the company should choose, assuming that air resistance, friction, and the weight of the cord can be ignored and that the cord immediately begins to stretch as soon as the jumper begins to fall? (Recall that g = 9.8 m/s)

University Physics Volume 1
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Chapter8: Potential Energy And Conservation Of Energy
Section: Chapter Questions
Problem 57P: In a Coyote/Road Runner cartoon clip (https://openstaxcollege.org/l/21coyroadcarcl), a spring...
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A bungee jumping company wants to set up a bungee jumping location on the top of a bridge that is 300 m above the ground. For safety reasons, the company wants to select a bungee cord spring constant such that a jumper with a mass of 115 kg will reach his lowest point – that is, the point when the change in gravitational potential energy equals the amount of energy stored in the bungee cord at the bottom of the jump at 50 m above the ground. What is the approximate spring constant the company should choose, assuming that air resistance, friction, and the weight of the cord can be ignored and that the cord immediately begins to stretch as soon as the jumper begins to fall? (Recall that g = 9.8 m/s)
Expert Solution
Step 1

SOlution:

Given that

Mass of the jumper, m = 115 kg

Height of the bridge, H =300 m

Height of the jumper at the lowest point,  h=50 m

So the extension in string is x = (300-50)=250 m

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