A business manager who needs to make many phone calls has estimated that when she calls a client, the probability that she will reach the client right away is 50%. If she does not reach the client on the first call, the probability that she will reach the client on her second call in the next hour is 20%. And if she does not reach the client on either the first or second call, the probability that the will reach the client on her third call in the hours after that is 10%. What is the probability that the manager will reach her client in three or fewer calls? What probability distribution did you use to solve this?

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter11: Data Analysis And Probability
Section11.8: Probabilities Of Disjoint And Overlapping Events
Problem 2C
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A business manager who needs to make many phone calls has estimated that when she calls a client, the probability that she will reach the client right away is 50%. If she does not reach the client on the first call, the probability that she will reach the client on her second call in the next hour is 20%. And if she does not reach the client on either the first or second call, the probability that the will reach the client on her third call in the hours after that is 10%. What is the probability that the manager will reach her client in three or fewer calls?

What probability distribution did you use to solve this?

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