please solve question 6 and the last one 79101213The partial fraction for the function-(A)(C)dx=I started states4-e[3x²e²dx=Le'de=4x+A₂ A₂x+4₂2+1 (x²+1)(A) 14x+4 Ax+A²+1 (x²+1)(A) sin(C) x=2 tanx-1(x-1)The suitable substitution for the integral√x-√x dx is (A) x-u(B) x-²Determine the values of p for which the integral [(x-4) is improper (A) p<1 (9) >1 (p=0 (p=1(8) 4(c) 3(D) The integral divergesWhich of the following is not an improper integral (A) [tan x dedx(A) 2e" (x²-1)+c(A) e1(B)-sin(8) O(8)fe2LIE(D)2(D) x-3 tantan x de (8) cotx ds to(s)+0Ax-1 (x-1)³4₂x+4₂ZIN(C) 2 sinh 2<<-2e2√4-(C) e ¹x² +c(C)+C{D) 2 sinh 3(D)(D) tan(D) x="2dx(D) e¹¹ (x²-1)+c

Answered: Image /qna-images/answer/b9148138-8c50-4074-a1c4-ac6eabf8bb11.jpg

Answered: (A) (C) x-1 Ax+A₂ Ax+A₂ (x-1) +1…

Math

Calculus

(A) (C) x-1 Ax+A₂ Ax+A₂ (x-1) +1 (x²+1)² 4x+4 Ax+A (8) (al x-1

College Algebra

7th Edition

ISBN:9781305115545

Author:James Stewart, Lothar Redlin, Saleem Watson

Publisher:James Stewart, Lothar Redlin, Saleem Watson

Chapter5: Systems Of Equations And Inequalities

Section5.3: Partial Fractions

Problem 12E

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Question

please solve question 6 and the last one

7
9
10
12
13
The partial fraction for the function-
(A)
(C)
dx=
I started states
4-e
[3x²e²dx=
Le'de=
4x+A₂ A₂x+4₂
2+1 (x²+1)
(A) 1
4x+4 Ax+A
²+1 (x²+1)
(A) sin
(C) x=2 tan
x-1(x-1)
The suitable substitution for the integral√x-√x dx is (A) x-u
(B) x-²
Determine the values of p for which the integral [(x-4) is improper (A) p<1 (9) >1 (p=0 (p=1
(8) 4
(c) 3
(D) The integral diverges
Which of the following is not an improper integral (A) [tan x de
dx
(A) 2e" (x²-1)+c
(A) e
1
(B)-sin
(8) O
(8)
fe
2
LIE
(D)
2
(D) x-3 tan
tan x de (8) cotx ds to
(s)
+0
A
x-1 (x-1)³
4₂x+4₂
ZIN
(C) 2 sinh 2
<<-2e
2√4-
(C) e ¹x² +c
(C)
+C
{D) 2 sinh 3
(D)
(D) tan
(D) x="
2
dx
(D) e¹¹ (x²-1)+c

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