A cable that weighs 3 lb/ft is used to lift 700 lb of coal up a mine shaft 450 ft deep. Find the work W done. Approximate the required work by a Riemann sum. W = lim > 3r;Ar i=1 W = lim )3.r;Ax + 700 · 450 i=1 72 W = lim 5r2 i-1 W = lim 3x;*Ar i=1 3 W = lim >-x;Ax+700 · 450 i=1 Express the work as an integral. 450 W = 3rdr 450 3 W = •450 3 W = I zrdr + 700 . 450 C450 3 xdr W = »450 W = 3rdr + 700 · 450 Evaluate the integral. | ft-lb W =

Mathematics For Machine Technology
8th Edition
ISBN:9781337798310
Author:Peterson, John.
Publisher:Peterson, John.
Chapter39: Symbolism And Algebraic Expressions
Section: Chapter Questions
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A cable that weighs 3 lb/ft is used to lift 700 lb of coal up a mine shaft 450 ft deep. Find the work W done.
Approximate the required work by a Riemann sum.
72
lim 3r;Ar
W =
i=1
72
W = lim )3.x; Ax + 700 - 450
i=1
72
3
W = lim >5T
i=1
72
W = lim 3r; Ax
i=1
72
3
W = lim
5t;Ar+ 700 .450
i=1
Express the work as an integral.
r450
W =
3rdr
•450
3
x²dx
W =
450 3
W =
I zrdr + 700 - 450
450 3
W =
xdx
450
W =
3.xd.x + 700 .450
Evaluate the integral.
W =
ft-lb
Transcribed Image Text:A cable that weighs 3 lb/ft is used to lift 700 lb of coal up a mine shaft 450 ft deep. Find the work W done. Approximate the required work by a Riemann sum. 72 lim 3r;Ar W = i=1 72 W = lim )3.x; Ax + 700 - 450 i=1 72 3 W = lim >5T i=1 72 W = lim 3r; Ax i=1 72 3 W = lim 5t;Ar+ 700 .450 i=1 Express the work as an integral. r450 W = 3rdr •450 3 x²dx W = 450 3 W = I zrdr + 700 - 450 450 3 W = xdx 450 W = 3.xd.x + 700 .450 Evaluate the integral. W = ft-lb
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ISBN:
9781337798310
Author:
Peterson, John.
Publisher:
Cengage Learning,