(a) Calculate the rate of heat conduction (in W) through house walls that are 11.5 cm thick and that have an average thermal conductivity twice that of glass wool. Assume there are no windows or doors. The surface area of the walls is 150 m? and their inside surface is at 20.0°C, while their outside surface is at 5.00°c. 1560 (b) How many 1 kW room heaters would be needed to balance the heat transfer due to conduction? (Round your answer to the next whole integer.) 1 kW room heaters (a) Calculate the rate of heat conduction (in W) through house walls that are 11.5 cm thick and that have an average thermal conductivity twice that of glass wool. Assume there are no windows or doors. The surface area of the walls is 150 m? and their inside surface is at 20.0°C, while their outside surface is at 5.00°C. 1565.21 x w (b) How many 1 kW room heaters would be needed to balance the heat transfer due to conduction? (Round your answer to the next whole integer.) 1 kW room heaters now from O we have, (20-04)x 150 X (20-0 - 50) (11.5 Xt6") -----> NOT THE ANSWER = 1.56 x10° w

(a) Calculate the rate of heat conduction (in W) through house walls that are 11.5 cm thick and that have an average thermal conductivity twice that of glass wool. Assume there are no windows or doors. The surface area of the walls is 150 m? and their inside surface is at 20.0°C, while their outside surface is at 5.00°c. 1560 (b) How many 1 kW room heaters would be needed to balance the heat transfer due to conduction? (Round your answer to the next whole integer.) 1 kW room heaters (a) Calculate the rate of heat conduction (in W) through house walls that are 11.5 cm thick and that have an average thermal conductivity twice that of glass wool. Assume there are no windows or doors. The surface area of the walls is 150 m? and their inside surface is at 20.0°C, while their outside surface is at 5.00°C. 1565.21 x w (b) How many 1 kW room heaters would be needed to balance the heat transfer due to conduction? (Round your answer to the next whole integer.) 1 kW room heaters now from O we have, (20-04)x 150 X (20-0 - 50) (11.5 Xt6") -----> NOT THE ANSWER = 1.56 x10° w

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter1: Temperature And Heat

Section: Chapter Questions

Problem 100P: One easy way to reduce heating (and cooling) costs is to add extra insulation in the attic of a...

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