Solve the following question using the quadratic formula.A cannonball fired from a cannon will follow the path of the parabola that is the graph of y = y(x), where y = -16(1 + s-)2+ sx feet. Here s is the slope of inclination of the cannon barrel, v, is the initial velocity in feet per second, and the variable x is thedistance downrange in feet. Suppose that a cannon is elevated with a slope of 0.5 (corresponding to an angle of inclination of about 27 degrees) and the cannonball is given an initial velocity of 230 feet per second. How far will the cannonball travel?ftNeed Help?Read ItE Show My Work (Optional) ?Submit Answer

To find the distance travelled by the cannon ball

A cannonball fired from a cannon will follow the path of the parabola that is the graph of y = y(x), where y = -16(1 + s ) + + sx feet. Here s is the slope of inclination of the cannon barrel, v, is the initial velocity in feet per second, and the variable distance downrange in feet. Suppose that a cannon is elevated with a slope of 0.5 (corresponding to an angle of inclination of about 27 degrees) and the cannonball is given an initial velocity of 230 feet per second. How far will the cannonball travel? ft Need Help? Read iI

A cannonball fired from a cannon will follow the path of the parabola that is the graph of y = y(x), where y = -16(1 + s ) + + sx feet. Here s is the slope of inclination of the cannon barrel, v, is the initial velocity in feet per second, and the variable distance downrange in feet. Suppose that a cannon is elevated with a slope of 0.5 (corresponding to an angle of inclination of about 27 degrees) and the cannonball is given an initial velocity of 230 feet per second. How far will the cannonball travel? ft Need Help? Read iI

Algebra and Trigonometry (MindTap Course List)

4th Edition

ISBN:9781305071742

Author:James Stewart, Lothar Redlin, Saleem Watson

Publisher:James Stewart, Lothar Redlin, Saleem Watson

Chapter3: Polynomial And Rational Functions

Section3.CT: Chapter Test

Problem 3CT: A cannonball fired out to sea from a shore battery follows a parabolic trajectory given by the graph...

See similar textbooks

Similar questions

A toy rocket shot upward from the ground at a rate of 208 ft/sec has the quadratic equation of h=16t2+208t . When will the rocket reach its maximum height? What will be the maximum height? Round answers to the nearest tenth.
Solve, rounding answers to the nearest tenth. The quadratic function h(x)=16t2+128t+32 is used to find the height of a stone thrown upward from a height of 32 feet at a rate of 128 ft/sec. How long will it take for the stone to reach its maximum height? What is the maximum height?
Find the intercepts of the parabola whose function is f(x)=3x2+4x+4.
A cannonball fired out to sea from a shore battery follows a parabolic trajectory given by the graph of the equation h(x)=10x0.01x2 where h(x) is the height of the cannonball above the water when it has traveled a horizontal distance of x feet. a What is the maximum height that the cannonball reaches? b How far does the cannonball travel horizontally before splashing into the water?