A cantilever beam of length 4m with a square section of side length 0.1 m is loaded vertically at the free end. The vertical displacement at the free end is 10mm. The beam is made of steel with Young's modulus of 4.0 x 1011 N/m². The maximum bending stress at the fixed end of the cantilever is
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- A simply supported 4-m long beam is made up of 80% grade Kato. The beam is carrying a uniform load of 12 KN/m all through out its length and a concentrated load of 800 N 1 meter from the left support. The cross-sectional area of the beam is indicated below. a. What is the moment of inertia (in mm4) of the cross-section of the beam? b. What is the value of Q (in mm3)? c. What is the actual bending stress of the beam in MPa? d. What is the actual shearing stress of the beam in MPa?The deck of a bridge consists of ribbed metal deck with100mm concrete slab on top. The deck is supported by wide flange steelbeams strengthened by cover plates 16mmx250mm one at the top and oneat the bottom. The beams are simply supported over a span of 25m andare spaced at 1.20m on centers. The beam loads are shown below. Unitweight of concrete is 23.50kN/m3. a.) Determine the maximum bending stress in the cover plated beam dueto live load plus impact, MPa b.) Determine the average web shear stress in the beam due to liveload plus impact, MPa.The rigid beam ABC is supported by a pin connection at C and by steel rod (1), which has a diameter of 7 mm. If the normal stress in rod (1) must not exceed 215 MPa, what is the maximum uniformly distributed load w that may be applied to beam ABC? What is the allowable force in road (1)? Use dimensions of a = 350 mm, b = 700 mm, and c = 525.0 mm.
- A cantilever beam of length 4 m, is subjected to an Uniformly distributed load of 26 kN/m for entire span. It has a hollow circular cross section of outer diameter 200 mm with the wall thickness of 30mm. Find (i) The maximum bending moment, (ii)Maximum bending stress induced, (iii) Radius of curvature, (iv) bending stress at half of outer diameter from the top surface of beam. Take E as 100 GPa. The maximum bending moment (in Nm) = Maximum Bending stress induced (in MPa) = Radius of curvature (in m) = Bending Stress at half of outer diameter from top surface (in N/m2) =A 4-m span wooden beam with rectangular section simply supports a uniform distributed loading of w=12.78 in KN/m. One support (roller) is located 1-m from the left end and the other support (hinged) is located at the right end of the span. The allowable bending stress is 9 MPa and the allowable shearing stress is 0.60 MPa. Neglect the beam weight and assume the beam to have a depth to width ratio of 1.50. What is the width of the beam so that it will not exceed the allowable shearing stress?PLEASE ANSWER ASAP TY! A 2-m long cantilever beam carries a uniformly distributed load of 10KN/m over its entire length. The beam has a rectangular cross-section with dimensions 200 mm wide and 400mm high. a) Determine the maximum flexure stress in the beam (in MPa). b) Determine the moment of inertia about the neutral axis of the cross-section (in mm4) c) Determine the magnitude of bending moment at a section 0.5m from fixed support (in KN-m). d) Determine the absolute maximum bending moment along the length of the beam (in KN-m).
- The simply supported beam of length L carries a uniformly distributed load of intensity w0 overthe span of the beam. Determine (a) the equation of the elastic curve, and (b) the maximumdisplacement.a.) Compute the maximum bending moment of this beamb) The base of the beam is 200mm and the allowable flexural stress of the beam is 70 MPa, design the depth of the beam.A steel beam having a simple span of 8 m. is subjected to a clockwise moment M at the left end and 25% of M (counter clockwise) at the right end. The steel section has the following properties. Fy = 248 MPa rt = 0.053 m d = 0.533 m bf = 0.210 m tf = 0.016 m Sx = 0.00206 m^3 1. Compute for the maximum slenderness ratio of the beam which is considered as long beam. 2. Compute the allowable bending stress in the compression flange. 3. Compute for the value of the moment at the left end.
- A W460×60 steel beam is loaded as shown. Assume w = 40 kN/m, M0 = 60 kN·m, LAB = 3.9 m, LBC = 1.6 m, E = 200 GPa, and I = 255 x 106 mm4.(a) Determine the reaction force at roller B.(b) Determine the maximum positive bending moment in the span.(c) If the allowable bending stress is 210 MPa, determine the minimum acceptable section modulus for the steel beam. Remove roller B. Determine the deflection at point B caused by the distributed load vw and by the moment vMo. Upward deflection is positive.Answer:vw = mmvMo = mmA steel beam is 24 inches tall, has a length, L, of 32ft, and has a yield stress of 36ksi. The simply supported beam supports a single load, P, of 17 kips at its midspan. If the theoretical maximum deflection of this beam is -(PL^3)/(48EI), determine the required moment of inertia such that the actual deflection of the beam will not exceed a value of L/360, and the actual stress will have a factor safety of 1.5 with respect to yielding.A simply supported beam AB = 10 m has a hollow rectangular cross-section with 14 cm as width, 23 cm as depth, and inner thickness as 1 cm is subjected to a point load of 7 N & 5 N acting at C and D respectively and a uniformly distributed load (UDL) of 7 N/m starts from mid-span and ends at the right support of the beam. Determine the maximum bending stress and the bending stress at 1 cm from the top. Take AC = 2 m & CD = 1 m. Solution: i) Reaction force at B = Answer and unit for part 1 ii) Reaction Force at A = Answer and unit for part 2 iii) The distance from B at which the shear Force value changes from "-" to "+" = Answer and unit for part 3 iv) Maximum Bending Moment (Please write the Maximum bending moment valve in "Nm") = Answer and unit for part 4 v) Moment of Inertia, I = Answer and unit for part 5 vi) Maximum bending stress = Answer and unit for part 6 vii) Bending stress at 1 cm from the top =