A car drives around a circular track of diameter 67 m at a constant speed of 35.5 m/s. During the time it takes the car to travel 157 degrees around, what is the magnitude of the car s average acceleration? O m/s^2 37.62 m/s^2 O 18.81 m/s^2 26.91 m/s^2
A car drives around a circular track of diameter 67 m at a constant speed of 35.5 m/s. During the time it takes the car to travel 157 degrees around, what is the magnitude of the car s average acceleration? O m/s^2 37.62 m/s^2 O 18.81 m/s^2 26.91 m/s^2
An Introduction to Physical Science
14th Edition
ISBN:9781305079137
Author:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres
Publisher:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres
Chapter2: Motion
Section2.4: Acceleration In Uniform Circular Motion
Problem 2.6CE
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You can use the formula for centripetal acceleration OR You have to calculate the average acceleration directly from the definition, a = delta v / delta t. You have to first get a_x by using the velocity's initial and final x components, do a_y from the y components, and then use the Pythagorean formula to get the magnitude of the acceleration vector.
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