A car has a drag coefficient Ca = 0.30, a frontal area of A = 1.9 m² and a mass 1.2 tonnes. It has a coefficient of rolling resistance, C,, = 0.012. The rolling resistance is a force F, = C,N, where N is the normal force. %3D i) What is F, when traveling at v = 110 kph on a horizontal road? F= N, Hint: Retain accurate values until the final calculation, but remember significant figures. Enter answer here . #664b] Car physics, part 2. Using the information from #664a above: ii) What power (in kilowatts) is required to overcome F, at this speed? P= kW . Hint: Retain accurate values until the final calculation, but remember significant figures. Enter answer here . (#665] Car physics, part 3 A car has a drag coefficient Ca = 0.30, a frontal area of A = 1.9 m² , a mass 1.2 tonnes and a coefficient of rolling resistance, C,, = 0.012. It is travelling up a hill with a slope of 1 in 20 at 110 kph. At what rate is it doing work against gravity (i.e. at what rate is it increasing its gravitational potential energy)? Pg = kW. (A 1:20 grade means that it rises 1 m for every 20 m travelled along the road: sin(0) = 1/20.) Enter answer here

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5. [#664a] Car physics, part 2.
A car has a drag coefficient Ca = 0.30, a frontal area of A = 1.9 m² and a mass 1.2 tonnes. It has a coefficient of rolling
resistance, C, = 0.012. The rolling resistance is a force F, = C,N, where N is the normal force.
i) What is F, when traveling at v =
110 kph on a horizontal road? F=
N,
Hint: Retain accurate values until the final calculation, but remember significant figures.
Enter answer here
6. [#664b] Car physics, part 2.
Using the information from #664a above:
ii) What power (in kilowatts) is required to overcome F, at this speed? P=
kW .
Hint: Retain accurate values until the final calculation, but remember significant figures.
Enter answer here
7. [#665] Car physics, part 3
A car has a drag coefficient Ca = 0.30, a frontal area of A = 1.9 m² , a mass 1.2 tonnes and a coefficient of rolling
resistance, Cr, = 0.012. It is travelling up a hill with a slope of 1 in 20 at 110 kph. At what rate is it doing work against
gravity (i.e. at what rate is it increasing its gravitational potential energy)?
Pg =
kW.
(A 1:20 grade means that it rises 1 m for every 20 m travelled along the road: sin(0) = 1/20.)
Enter answer here
Transcribed Image Text:5. [#664a] Car physics, part 2. A car has a drag coefficient Ca = 0.30, a frontal area of A = 1.9 m² and a mass 1.2 tonnes. It has a coefficient of rolling resistance, C, = 0.012. The rolling resistance is a force F, = C,N, where N is the normal force. i) What is F, when traveling at v = 110 kph on a horizontal road? F= N, Hint: Retain accurate values until the final calculation, but remember significant figures. Enter answer here 6. [#664b] Car physics, part 2. Using the information from #664a above: ii) What power (in kilowatts) is required to overcome F, at this speed? P= kW . Hint: Retain accurate values until the final calculation, but remember significant figures. Enter answer here 7. [#665] Car physics, part 3 A car has a drag coefficient Ca = 0.30, a frontal area of A = 1.9 m² , a mass 1.2 tonnes and a coefficient of rolling resistance, Cr, = 0.012. It is travelling up a hill with a slope of 1 in 20 at 110 kph. At what rate is it doing work against gravity (i.e. at what rate is it increasing its gravitational potential energy)? Pg = kW. (A 1:20 grade means that it rises 1 m for every 20 m travelled along the road: sin(0) = 1/20.) Enter answer here
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