A car has a drag coefficient Ca = 0.30, a frontal area of A = 1.9 m² and a mass 1.2 tonnes. It has a coefficient of rolling resistance, C,, = 0.012. The rolling resistance is a force F, = C,N, where N is the normal force. %3D i) What is F, when traveling at v = 110 kph on a horizontal road? F= N, Hint: Retain accurate values until the final calculation, but remember significant figures. Enter answer here . #664b] Car physics, part 2. Using the information from #664a above: ii) What power (in kilowatts) is required to overcome F, at this speed? P= kW . Hint: Retain accurate values until the final calculation, but remember significant figures. Enter answer here . (#665] Car physics, part 3 A car has a drag coefficient Ca = 0.30, a frontal area of A = 1.9 m² , a mass 1.2 tonnes and a coefficient of rolling resistance, C,, = 0.012. It is travelling up a hill with a slope of 1 in 20 at 110 kph. At what rate is it doing work against gravity (i.e. at what rate is it increasing its gravitational potential energy)? Pg = kW. (A 1:20 grade means that it rises 1 m for every 20 m travelled along the road: sin(0) = 1/20.) Enter answer here
A car has a drag coefficient Ca = 0.30, a frontal area of A = 1.9 m² and a mass 1.2 tonnes. It has a coefficient of rolling resistance, C,, = 0.012. The rolling resistance is a force F, = C,N, where N is the normal force. %3D i) What is F, when traveling at v = 110 kph on a horizontal road? F= N, Hint: Retain accurate values until the final calculation, but remember significant figures. Enter answer here . #664b] Car physics, part 2. Using the information from #664a above: ii) What power (in kilowatts) is required to overcome F, at this speed? P= kW . Hint: Retain accurate values until the final calculation, but remember significant figures. Enter answer here . (#665] Car physics, part 3 A car has a drag coefficient Ca = 0.30, a frontal area of A = 1.9 m² , a mass 1.2 tonnes and a coefficient of rolling resistance, C,, = 0.012. It is travelling up a hill with a slope of 1 in 20 at 110 kph. At what rate is it doing work against gravity (i.e. at what rate is it increasing its gravitational potential energy)? Pg = kW. (A 1:20 grade means that it rises 1 m for every 20 m travelled along the road: sin(0) = 1/20.) Enter answer here
Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter11: Gravity, Planetary Orbits, And The Hydrogen Atom
Section: Chapter Questions
Problem 28P
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