A car is traveling along a straight road at a velocity of +38.1 m/s when its engine cuts out. For the next 1.96 seconds, the car slows down, and its average acceleration is a,. For the next 3.45 seconds, the car slows down further, and its average acceleration is ā₂. The velocity of the car at the end of the 5.41-second period is +29.6 m/s. The ratio of the average acceleration values is ā,/a₂=1.44. Find the velocity of the car at the end of the initial 1.96-second interval.

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter2: Motion In One Dimension
Section: Chapter Questions
Problem 23P: The driver of a car slams on the brakes when he sees a tree blocking the road. The car slows...
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I understand to solve this practice problem for each acceleration, I do the change in velocity/change in time and that the only thing I'm missing is the speed at the end of the first time interval. I just can't figure out exactly how to configure the problem. 

A car is traveling along a straight road at a velocity of +38.1 m/s when its engine cuts out. For the next 1.96 seconds, the car slows
down, and its average acceleration is a,. For the next 3.45 seconds, the car slows down further, and its average acceleration is ₂. The
velocity of the car at the end of the 5.41-second period is +29.6 m/s. The ratio of the average acceleration values is a,/₂ = 1.44. Find
the velocity of the car at the end of the initial 1.96-second interval.
Transcribed Image Text:A car is traveling along a straight road at a velocity of +38.1 m/s when its engine cuts out. For the next 1.96 seconds, the car slows down, and its average acceleration is a,. For the next 3.45 seconds, the car slows down further, and its average acceleration is ₂. The velocity of the car at the end of the 5.41-second period is +29.6 m/s. The ratio of the average acceleration values is a,/₂ = 1.44. Find the velocity of the car at the end of the initial 1.96-second interval.
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