A cat rides a merry-go-round while turning with uniform circular motion. At time t = 2.00 s, the cat's velocity is v, = (3.50)î + (4.00 m/s) j, measured on a horizontal xy coordinate system. At time t2 = 6.00 s, a half-revolution later, its velocity is v2 = (-3.50 m/s)î + (-4.00 m/s)ĵ. (a) What is the magnitude of the cat's centripetal acceleration? m/s2 (b) What is the magnitude of the cat's average acceleration during the time interval tz - t? m/s2 Submit Answer

A cat rides a merry-go-round while turning with uniform circular motion. At time t = 2.00 s, the cat's velocity is v, = (3.50)î + (4.00 m/s) j, measured on a horizontal xy coordinate system. At time t2 = 6.00 s, a half-revolution later, its velocity is v2 = (-3.50 m/s)î + (-4.00 m/s)ĵ. (a) What is the magnitude of the cat's centripetal acceleration? m/s2 (b) What is the magnitude of the cat's average acceleration during the time interval tz - t? m/s2 Submit Answer

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Description: A cat rides a merry-go-round while turning with uniform circular motion. At time t, = 2.00 s, the cat's velocity is v1 = (3.50)î + (4.00 m/s) î, measured on a horizontal xycoordinate system. At time t2 = 6.00 s, a half-revolution later, its velocity

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter3: Motion In Two Dimensions

Section: Chapter Questions

Problem 3OQ: Figure OQ3.3 shows a birds-eye view of a car going around a highway curve. As the car moves from...

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A cat rides a merry-go-round turning with uniform circular motion. At time t1 = 2.20 s, the cat's velocity is (3.80 m/s) i^ + (3.40 m/s) j^, measured on a horizontal xy coordinate system. At t2 = 5.10 s, its velocity is (-3.80 m/s) i^ + (-3.40) j^. What are (a) the magnitude of the cat's centripetal acceleration and (b) the magnitude of the cat's average acceleration during the time interval t2 – t1, which is less than a period of the motion? I just need (b) solved. It's not 4.45.
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