
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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A certain material has a thickness of 30 cm and a thermal
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- dT Newton's law of cooling states that the rate of change in the temperature T(t) of a body is proportional to the difference between the temperature of the medium M(t) and the temperature of the body. That is, = K[M(t) - T(t)), where dt Kis a constant. Let K= 0.04 (min)' and the temperature of the medium be constant, M(t) = 290 kelvins. If the body is initially at 352 kelvins, use Euler's method with h =0.1 min to approximate the temperature of the body after (a) 30 minutes and (b) 60 minutes. (a) The temperature of the body after 30 minutes is 308.62 kelvins. (Round to two decimal places as needed.) (b) The temperature of the body after 60 minutes is kelvins. (Round to two decimal places as needed.)arrow_forwardA hot steel plate with a surface area of 2.47 m2 and a constant surface temperature of 161°C is exposed to ambient air at 23°C. If the convection heat transfer coefficient is 18.2 W/m2· K, what is the rate of heat transfer (in W) from the plate to the air [round your final answer to zero decimal places]?arrow_forwardNewton's Law of Cooling The temperature of a cup of coffee t min after it is poured is given by the following equation where T is measured in degrees Fahrenheit. T = 65 + 90e−0.068t (a) What was the temperature (in degrees Fahrenheit) of the coffee when it was poured? ____ °F (b) When (in minutes) will the coffee be cool enough to drink (say, 120°F)? (Round your answer to one decimal place.) ______minarrow_forward
- When the indoor temperature of a house is 25°C and the outdoor temperature is -8°C, the inside and outside surfaces of the glass are measured to be 21.3°C and 17.3°C. If the glass has an area of 3.16 m2 and a thickness of 6.14 mm, what is the rate of heat (in W) lost though the window? {kglass = 0.78 W/m∙K}arrow_forwardLuis and Salman are trying to increase the temperature of a substance by heating it. . What is the quantity of heat in kilojoules required to raise the temperature of 1.2 kg of the substance from3°C to 110 °C at a pressure of 1.0 atm? Please keep three significant figures. Useful information: Melting point = 293 K heat of fusion = 3.90 x 104 J/kg. boiling point is 423 K heat of vaporization 7.80 x 104 J/kg (at a pressure of 1.0 atm). The specific heats for the solid phase is 600 J/(kg K) The specific heats for the liquid phase is 1000 J/(kg K) The specific heats for the gaseous phase is 400 J/(kg K)arrow_forwardNewton's Law of Cooling The temperature of a cup of coffee t min after it is poured is given by the following equation where T is measured in degrees Fahrenheit. T = 65 + 110e−0.053t (a)What was the temperature (in degrees Fahrenheit) of the coffee when it was poured?_________ °F (b)When (in minutes) will the coffee be cool enough to drink (say, 120°F)? (Round your answer to one decimal place.)_______ minarrow_forward
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