A Channel C6x13 is used as a tension member. The holes are for 5/8 inch in diameter of bolts. Using A36 steel with Fy=36 ksi and Fu=58 ksi. The gross area of C6x13 is 3.81 in² and Assume U=0.85 Using LRFD what is the design strength based on Tensile Rupture/Fracture 4 @ 2" ... a 1 1/2 " Ob 3" Oc 1 1/2 " I d e Со х 13
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- Determine the effective net area of the L7 × 4 × 1/2 shown in the figure. Assume the holes are for 1-in Ø bolts. Use the U values given in Table 3.2. (Ans. 3.97 in^2)Steel design. The lap joint shown consist of bolts 22mm in diameter in 25mm diameter holes, The plates are A36 steel with Fy=250MPa, and Fu=400MPa. Use x1=50 mm ,x2= 160mm ,x3=60mm and plate thickness t=12mm for this problem. The allowable stress are: Bearing stress on project are,Fc=1.5Fu Tension on the net area of plates,Ft=0.5Fu Shear on the plates, Fv=0.3Fu Shear strength of bolt,Fv=210MPa Det. the value of Load P based on bolt shear Det. the value of Load P base on bearing on projected area on plate. Det. the value of load P based on block shearDetermine the nominal tensile strength of the single angle. Consider 7/8" diameter bolt and A242 steel with Fy = 50 ksi and Fu = 70 ksi. L6x6x3/4 d = 6 in. b = 6 in. t = 0.75 in. k = 1.25 in. wt./ft. = 28.8 plf. A = 8.46 in.^2 x = 1.77 in.
- A double-angle shape, 2L7 3 4 3 3⁄8, is used as a tension member. The twoangles are connected to a gusset plate with 7⁄8-inch-diameter bolts throughthe 7-inch legs, as shown in Figure P3.4-5. A572 Grade 50 steel is used.a. Compute the design strength.b. Compute the allowable strength.an angle bar 100x100x11 mm tension member is connected with 20-mm-dia bolts as shown in the fig. both legs of the angles are connected. use fy=248 MPa and Fu=400 MPa. 1. determine the nominal strength for tensile yielding in the gross section. a. 515.59 kN b. 429.67 kN c. 545.60 kN d. 390.10 kN 2. determine the effective net area of member a. 1573 mm^2 b. 1632 mm^2 c. 1605 mm^2 d. 1815 mm^2 3. determine the nominal strength for tensile rupture in the net area. a. 642 kN b. 730 kN c. 554 kN d. 650 kNThe 1 × 8 plate is shown in the figure. The holes are for 3/4-in Ø bolts. Compute the net area of each of the given members. (Ans. 6.44 in^2)
- 5. a bolted lap joint shown in the figure below. The bolts are 20m in diameter in 23 mm holes. The plates are 12m thick X350 Allowable stress of Plates: Tenaion in gross area0.60Fy Tension in net area0.50 Fu Shear on Net Area 0.30Fu Yield Strength of plate, Fy 248 Npa Ultinate tensile strength of Plate. Fu400 Mpa x, Find the safe load P based on a- Gross area yielding b. net area rapture c. block shear 2 of 3The bolts in the lap joint shown are 22mm in diameter and 25mm diameter holes. The plates are A36 steel with Fy = 250MPa and Fu = 400Mpa. For this problem, x1 = 500mm, x2 = 160mm, x3 = 60mm and t = 12mm. The allowable stresses are: Bearing Stress on projected area of the plates Fp = 1.5Fu Tension on net area of plates, Ft = 0.5Fu Shear on plates, Fy= 0.3Fu Shear strength of bolt, Fv= 210 Mpa a.) Determine the value of P based on bolt shear b.) Determine the value of load P based on bearing on projected area on plate (area in contact with the plate and bolts) c.) Determine the value of P based on block shear (use net area for block shear and use the diameter of hole)0.1: An MC9x23.9 is connected with 3 /4-inch diameter bolts as shown below. A572 Grade 50 steel is used. Determine the design strength for the section.
- The plate shown is attached by using three M12x2 grade 8.8 bolts. Which screw is subjected to the largest stress? What safe load ( static) F can be supported by the screw for n=1.5.A 1 ⁄2 × 5-inch plate of A588 steel is used as a tension member. It is connected to a gusset plate with four 5 ⁄8-inch-diameter bolts as shown in Figure 1. Assume that the effective net area Ae equals the actual net area An. (a) Calculate the design strength for LRFD? (b) Calculate the allowable strength for ASD?A single-angle tension member 175 mm x 100 mm x 18 mm haw two gage lines in its long leg and one in the short leg for 16 mm bolts arranged as shown. Area of the angular section is 4961 mm^2. Use A36 steel Fy = 248 MPa and Fu = 400 MPa. Standard nominal hole diameter for 16 mm bolt = 17 mm. Determine the net area of the angular section. Determine the allowable tension strength of the angular section based on the gross area. Determine the allowable tensile strength of the angular section based on the effective net area. Reduction factor U = 0.75