A charge Q is placed in the center of a shell of radius R. The electric flux through the shell surface is $0. If we now double the radius of the shell, what happens to the flux through its surface? It will increase by a factor of 4 It will increase by a factor of 2 It will decrease by a factor of 4 It will decrease by a factor of 2 It remains unchanged none of these

College Physics
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ISBN:9781285737027
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter15: Electric Forces And Electric Fields
Section: Chapter Questions
Problem 52P: A charge of 1.70 102 C is at the center of a cube of edge 80.0 cm. No other charges are nearby. (a)...
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A charge Q is placed in the center of a shell of radius R. The electric flux through the shell surface is
$0.
If we now double the radius of the shell, what happens to the flux through its surface?
It will increase by a factor of 4
It will increase by a factor of 2
It will decrease by a factor of 4
It will decrease by a factor of 2
It remains unchanged
none of these
Transcribed Image Text:A charge Q is placed in the center of a shell of radius R. The electric flux through the shell surface is $0. If we now double the radius of the shell, what happens to the flux through its surface? It will increase by a factor of 4 It will increase by a factor of 2 It will decrease by a factor of 4 It will decrease by a factor of 2 It remains unchanged none of these
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Given

Q charge is placed at the center of a shell and flux produced is Φo   .

If radius is doubled then what will happen to the flux.

 

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