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A Chemistry student at Agora is calculating the average atomic mass of Potassium using the following data. Relative abundance 93-12 % 6.88% Isotope K-39 K-41 Their setup and calculation are. Atomic Mass 38.964 amu 40.962 amu Mass (amu) X Relative Abundance (% divide by 100) 38.964 40.962 0.0688 0.9312 = 2.681 = 38.144 40.823 amu The student calculated the average atomic mass to be 40.823 amu but it is 39.098 amu on the periodic table. What did the student do incorrectly? Use CER!

A Chemistry student at Agora is calculating the average atomic mass of Potassium using the following data. Relative abundance 93-12 % 6.88% Isotope K-39 K-41 Their setup and calculation are. Atomic Mass 38.964 amu 40.962 amu Mass (amu) X Relative Abundance (% divide by 100) 38.964 40.962 0.0688 0.9312 = 2.681 = 38.144 40.823 amu The student calculated the average atomic mass to be 40.823 amu but it is 39.098 amu on the periodic table. What did the student do incorrectly? Use CER!

Chemistry by OpenStax (2015-05-04)
Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter2: Atoms, Molecules, And Ions
Section: Chapter Questions
Problem 22E: An element has the following natural abundances and isotopic masses: 90.92% abundance with 19.99...
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A Chemistry student at Agora is calculating the average atomic mass of Potassium using the following data. Relative abundance 93-12 % 6.88 % Isotope K-39 K-41 Their setup and calculation are. Atomic Mass 38.964 amu 40.962 amu Mass (amu) X Relative Abundance (% divide by 100) 38.964 40.962 0.0688 0.9312 = 2.681 = 38.144 40.823 amu The student calculated the average atomic mass to be 40.823 amu but it is 39.098 amu on the periodic table. What did the student do incorrectly? Use CER!
Transcribed Image Text:A Chemistry student at Agora is calculating the average atomic mass of Potassium using the following data. Relative abundance 93-12 % 6.88 % Isotope K-39 K-41 Their setup and calculation are. Atomic Mass 38.964 amu 40.962 amu Mass (amu) X Relative Abundance (% divide by 100) 38.964 40.962 0.0688 0.9312 = 2.681 = 38.144 40.823 amu The student calculated the average atomic mass to be 40.823 amu but it is 39.098 amu on the periodic table. What did the student do incorrectly? Use CER!
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