A child has a temperature of 101°F . If her total skin area is 19 m², find the energy loss per second due to radiation, as- suming the emissivity is 1. Assume the room temperature is 70°F. The Stephan-Boltzmann constant is 5.6696 × 10¬8 W/m² · K*. Answer in units of W.

University Physics Volume 2
18th Edition
ISBN:9781938168161
Author:OpenStax
Publisher:OpenStax
Chapter1: Temperature And Heat
Section: Chapter Questions
Problem 48P: A person taking a reading of the temperature in a freezer in Celsius makes two mistakes: first...
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A child has a temperature of 101°F.
If her total skin area is 19 m², find the
energy loss per second due to radiation, as-
suming the emissivity is 1. Assume the room
temperature is 70°F. The Stephan-Boltzmann
constant is 5.6696 × 10-8 w/m² · Kª .
2
Answer in units of W.
Transcribed Image Text:A child has a temperature of 101°F. If her total skin area is 19 m², find the energy loss per second due to radiation, as- suming the emissivity is 1. Assume the room temperature is 70°F. The Stephan-Boltzmann constant is 5.6696 × 10-8 w/m² · Kª . 2 Answer in units of W.
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