A child slides across a floor in a pair of rubber-soled shoes. The frictional force acting on each foot is 20.0 N. The footprint area of each shoe sole is 11.0 cm2, and the thickness of each sole is 5.80 mm. Find the horizontal distance by which the upper and lower surfaces of each sole are offset. The shear modulus of the rubber is 3.00 x 106 N/m2. mm

Physics for Scientists and Engineers, Technology Update (No access codes included)
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Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter12: Static Equilibrium And Elasticity
Section: Chapter Questions
Problem 12.28P: Assume Youngs modulus for bone is 1.50 1010 N/m2. The bone breaks if stress greater than 1.50 108...
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A child slides across a floor in a pair of rubber-soled shoes. The frictional force acting on each foot is 20.0 N. The footprint area of
each shoe sole is 11.0 cm2, and the thickness of each sole is 5.80 mm. Find the horizontal distance by which the upper and lower
surfaces of each sole are offset. The shear modulus of the rubber is 3.00 x 106 N/m².
mm
Assume if the shear stress in steel exceeds about 4.00 x 108 N/m2 the steel ruptures.
(a) Determine the shearing force necessary to shear a steel bolt 0.75 cm in diameter.
(b) Determine the shearing force necessary to punch a 2.60-cm-diameter hole in a steel plate 0.450 cm thick.
Transcribed Image Text:A child slides across a floor in a pair of rubber-soled shoes. The frictional force acting on each foot is 20.0 N. The footprint area of each shoe sole is 11.0 cm2, and the thickness of each sole is 5.80 mm. Find the horizontal distance by which the upper and lower surfaces of each sole are offset. The shear modulus of the rubber is 3.00 x 106 N/m². mm Assume if the shear stress in steel exceeds about 4.00 x 108 N/m2 the steel ruptures. (a) Determine the shearing force necessary to shear a steel bolt 0.75 cm in diameter. (b) Determine the shearing force necessary to punch a 2.60-cm-diameter hole in a steel plate 0.450 cm thick.
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