A circle can be defined by an equation x2 + y2 + ax + by + c = 0. Find an equation of a circle that passes through (-4, 1), (3, 0) and (5,4). Ox2 + y2 -8x +2y + 5 = 0 Ox2 + y2 -2x - 4 = 0 Ox2 + y2 + 2x - 8y + 5 = 0 Ox2 + y2 -8y - 9 = 0

Algebra & Trigonometry with Analytic Geometry
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ISBN:9781133382119
Author:Swokowski
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A circle can be defined by an equation x2 + y² + ax + by + c = 0. Find an equation of a
circle that passes through (-4, 1), (3, 0) and (5,4).
Ox2 + y2 -8x +2y + 5 = 0
Ox2 + y2 -2x - 4 = 0
Ox2 + y2 + 2x - 8y + 5 = 0
Ox2 + y2 -8y - 9 = 0
Transcribed Image Text:A circle can be defined by an equation x2 + y² + ax + by + c = 0. Find an equation of a circle that passes through (-4, 1), (3, 0) and (5,4). Ox2 + y2 -8x +2y + 5 = 0 Ox2 + y2 -2x - 4 = 0 Ox2 + y2 + 2x - 8y + 5 = 0 Ox2 + y2 -8y - 9 = 0
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