A circular cylinder of radius 1 and theparabolic cylinderz = 2y? – 1 intersect as shown inWhich vector functionr(t)x(t) i+ y(t)j+ z(t) khas the curve of intersection as its graph ifx(0) = 0?1. r(t)(sin t) i+ (cost) j+(1– cos 2t) k2. r(t) = (sin t)i+(cost) j+(cos 2t) k3. r(t) = (cost) i+(sin t) j+ (cos 2t) k4. r(t) = (sin t) i+(cos t) j+(cos 2t – 1) k5. r(t) — (сos t)і+(sint)j+ (1— сos 2t) k6. r(t) = (cos t) i+(sin t) j+(cos 2t – 1) k

In this question, we have to find the curve of intersection.

Answered: A circular cylinder of radius 1 and the…

Math

Calculus

A circular cylinder of radius 1 and the parabolic cylinder x = 2y? – 1 2 =

Elementary Geometry For College Students, 7e

7th Edition

ISBN:9781337614085

Author:Alexander, Daniel C.; Koeberlein, Geralyn M.

Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.

Chapter9: Surfaces And Solids

Section9.3: Cylinders And Cones

Problem 5E: For the right circular cylinder, suppose that r=5 in. and h=6 in. Find the exact and approximate a...

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Question

A circular cylinder of radius 1 and the
parabolic cylinder
z = 2y? – 1

intersect as shown in
Which vector function
r(t)
x(t) i+ y(t)j+ z(t) k
has the curve of intersection as its graph if
x(0) = 0?
1. r(t)
(sin t) i+ (cost) j+(1– cos 2t) k
2. r(t) = (sin t)i+(cost) j+(cos 2t) k
3. r(t) = (cost) i+(sin t) j+ (cos 2t) k
4. r(t) = (sin t) i+(cos t) j+(cos 2t – 1) k
5. r(t) — (сos t)і+(sint)j+ (1— сos 2t) k
6. r(t) = (cos t) i+(sin t) j+(cos 2t – 1) k

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