A circular disk with a radius of 0.38 m is subject to 2 tangentially applied forces. The disc is fixed such that it will rotate about its center. Both forces produce a torque in the same direction. The mass of the disc is 0.73 kg. The moment of inertia of a disc is I = 1/2 MR^2 F1 = 2.3 N applied at the outer edge of the disc. F2 = 3.6 N applied at a distance of 0.29 from the center of the disc. What is the angular acceleration of the disc?
A circular disk with a radius of 0.38 m is subject to 2 tangentially applied forces. The disc is fixed such that it will rotate about its center. Both forces produce a torque in the same direction. The mass of the disc is 0.73 kg. The moment of inertia of a disc is I = 1/2 MR^2 F1 = 2.3 N applied at the outer edge of the disc. F2 = 3.6 N applied at a distance of 0.29 from the center of the disc. What is the angular acceleration of the disc?
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A circular disk with a radius of 0.38 m is subject to 2 tangentially applied forces. The disc is fixed such that it will rotate about its center. Both forces produce a torque in the same direction. The mass of the disc is 0.73 kg. The moment of inertia of a disc is I = 1/2 MR^2
F1 = 2.3 N applied at the outer edge of the disc.
F2 = 3.6 N applied at a distance of 0.29 from the center of the disc.
What is the
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