A circular loop of resistance R=2.15 N and area A-0.08 m² is placed in a uniform magnetic field. From t-0 on, the field start varying with time according to B(t)=t2+20t+5, where B is in mT and t in seconds. Find the time t (in s) at which the current passing by the loop is 8.3 mA. R

Physics for Scientists and Engineers: Foundations and Connections
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Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter32: Faraday’s Law Of Induction
Section: Chapter Questions
Problem 79PQ: A conducting single-turn circular loop with a total resistance of 5.00 is placed in a time-varying...
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Consider Use them k=9.00×10^9 N.m^2/C^2 ε0= 8.85×10^-12 C^2/N.m^2 µ0=4π×10^-7 T.m/A mp=1.67×10^-27 kg me=9.11×10^-31 kg e=1.6×10^-19 C g=10.0 m/s^2
A circular loop of resistance R=2.15 N and area A=0.08 m² is placed in a uniform magnetic field. From t-0 on, the field start varying with time according to
B(t)=t2+20t+5, where B is in mT and t in seconds. Find the time t (in s) at which the current passing by the loop is 8.3 mA.
R.
Transcribed Image Text:A circular loop of resistance R=2.15 N and area A=0.08 m² is placed in a uniform magnetic field. From t-0 on, the field start varying with time according to B(t)=t2+20t+5, where B is in mT and t in seconds. Find the time t (in s) at which the current passing by the loop is 8.3 mA. R.
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